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SVETLANKA909090 [29]

3 years ago

8

How can you minimize the error while measuring the length of the body? Write any two precautions to be followed. please fast....

.. emergency..

1 answer:

Natalija [7]3 years ago

7 0

Answer: By double checking your work and by using quality equipment it minimizes the error while measuring the length of the body

Explanation:

Hopefully this helps

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If 40 kJ of heat energy are added to 4 kg of water at 30°C, what will be the final temperature of the water? The specific heat o

n200080 [17]

Heat gained or added in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:<span>

Heat = mC(T2-T1)
40000 = 4(4186)(T2 - 30.0)
<span>T2 = 32.4 degrees Celsius</span></span>

5 0

3 years ago

Two children are riding on the edge of a merry-go-round that has a mass of 100.kg and radius of 1.60m and is rotating at 20.0rpm

Gre4nikov [31]

Here since both children and merry go round is our system and there is no torque acting on this system

So we will use angular momentum conservation in this

$I_1\omega_1 = I_2\omega_2$

now here we have

$I_1 = \frac{MR^2}{2} + m_1R^2 + m_2R^2$

$I_1 = \frac{100(1.60)^2}{2} + (22 + 28)(1.60)^2$

$I_1 = 256$

Now when children come to the position of half radius

then we will have

$I_2 = \frac{MR^2}{2} + m_1(\frac{R}{2})^2 + m_2(\frac{R}{2})^2$

$I_2 = \frac{100(1.6)^2}{2} + (28 + 22)(0.8)^2$

$I_2 = 160$

now from above equation we have

$256 (20.0 rpm) = 160(\omega_2)$

$\omega_2 = 32 rpm$

8 0

3 years ago

A particle is located on the x axis 4.9 m from the origin. A force of 38 N, directed 30° above the x axis in the x-y plane, acts

Juli2301 [7.4K]

Answer:

Torque is 93 Nm anticlockwise.

Explanation:

We have value of torque is cross product of position vector and force vector.

A force of 38 N, directed 30° above the x axis in the x-y plane.

Force, F = 38 cos 30 i + 38 sin 30 j = 32.91 i + 19 j

A particle is located on the x axis 4.9 m and we have to find torque about the origin on the particle.

Position vector, r = 4.9 i

Torque, T = r x F = 4.9 i x (32.91 i + 19 j) = 4.9 x 19 k = 93.1 k Nm

So Torque is 93 Nm anticlockwise.

7 0

3 years ago

Suppose you apply a force of 75 N to a 25-kg object. What will the acceleration of the object be?

Serjik [45]

Answer:

I belive it would be ture

Explanation:

It's been a while since I learned this but I think that is right.

6 0

3 years ago

Read 2 more answers

Help and explain please

babunello [35]

Answer: a) Moment = 200N.m

b) F = 500N

Explanation: <u>Moment</u> or <u>Torque</u> is the tendency of a body to rotate because of an aplplied force. It can be calculated as

$\tau = F.r.sin\theta$

F is force applied

r is distance from the force to the point of rotation

θ is the angle formed between force and distance

a) Since F and r are perpendicular, θ=90°, sin90° = 1, so

$\tau=F.r$

$\tau=100(2)$

$\tau=$ 200

<u>Torque</u><u> caused by weight of the barrier at the pivot is </u><u>200N.m</u>

<u />

b) Counterweight has the same torque as pivot: $\tau=$ 200

So, to find Force necessary to balance the weight:

$\tau=F.r$

$F=\frac{\tau}{r}$

$F=\frac{200}{0.4}$

F = 500

<u>It is necessary </u><u>a force of 500N</u><u> from the counterweight to balance the weight.</u>

<u />

4 0

3 years ago