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3 years ago

Sugar is made of carbon, hydrogen, and oxygen atoms.Sugar is

Physics

1 answer:

patriot [66]3 years ago

4 0

Answer:

Matter is everything that surrounds us. It has mass and occupies a place in space. Matter can be described by measuring the value of its properties; for example: density, color, mass, volume, etc.

al ser homogenea no se puede percibir con la vista pero si se le agrega acido sulfurico la reaccion hara que el hidrogeno y el oxigeno se evaporen dejando unicamente una masa negra de carbono

No, ya que, es una mezcla homogénea, es decir, sus elementos están muy unidos mas no combinados de manera química, es posible separarlos pero con mucha dificultad, por tanto, es imposible diferenciarlos a simple vista. Se sabe que están distribuidos de manera uniforme, su estado es conocido como solución o disolución, tal como es el caso del azúcar.

Explanation:

I hope my answer serves you and that it is to your liking please give me cornita: 3

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2 years ago

Otherwise, Newton's First Law of Motion says that an object will continue to stay at rest or at a _____ until a force is applied

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3 years ago

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Two satellites are in circular orbits around the earth. The orbit for satellite A is at a height of 403 km above the earth’s sur

BARSIC [14]

Answer:

$v_A=7667m/s\\\\v_B=7487m/s$

Explanation:

The gravitational force exerted on the satellites is given by the Newton's Law of Universal Gravitation:

$F_g=\frac{GMm}{R^{2} }$

Where M is the mass of the earth, m is the mass of a satellite, R the radius of its orbit and G is the gravitational constant.

Also, we know that the centripetal force of an object describing a circular motion is given by:

$F_c=m\frac{v^{2}}{R}$

Where m is the mass of the object, v is its speed and R is its distance to the center of the circle.

Then, since the gravitational force is the centripetal force in this case, we can equalize the two expressions and solve for v:

$\frac{GMm}{R^2}=m\frac{v^2}{R}\\ \\\implies v=\sqrt{\frac{GM}{R}}$

Finally, we plug in the values for G (6.67*10^-11Nm^2/kg^2), M (5.97*10^24kg) and R for each satellite. Take in account that R is the radius of the orbit, not the distance to the planet's surface. So $R_A=6774km=6.774*10^6m$ and $R_B=7103km=7.103*10^6m$ (Since $R_{earth}=6371km$ ). Then, we get:

$v_A=\sqrt{\frac{(6.67*10^{-11}Nm^2/kg^2)(5.97*10^{24}kg)}{6.774*10^6m} }=7667m/s\\\\v_B=\sqrt{\frac{(6.67*10^{-11}Nm^2/kg^2)(5.97*10^{24}kg)}{7.103*10^6m} }=7487m/s$

In words, the orbital speed for satellite A is 7667m/s (a) and for satellite B is 7487m/s (b).

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2 years ago