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3 years ago

A 12.0 V battery has as 80.0 Ohm

Physics

1 answer:

Vesna [10]3 years ago

6 0

Potential difference=V=12V
Resistance=80ohm=R
Current be I

Using ohms law

$\\ \sf\longmapsto \dfrac{V}{I}=R$

$\\ \sf\longmapsto I=\dfrac{V}{R}$

$\\ \sf\longmapsto I=\dfrac{12}{80}$

$\\ \sf\longmapsto I=0.15A$

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Let the initial velocity of this projectile be $v_0$ .

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