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3 years ago

A 12.0 V battery has as 80.0 Ohm

Physics

1 answer:

Vesna [10]3 years ago

6 0

Potential difference=V=12V
Resistance=80ohm=R
Current be I

Using ohms law

$\\ \sf\longmapsto \dfrac{V}{I}=R$

$\\ \sf\longmapsto I=\dfrac{V}{R}$

$\\ \sf\longmapsto I=\dfrac{12}{80}$

$\\ \sf\longmapsto I=0.15A$

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Bob’s wife is in her third trimester of pregnancy. Bob’s _________ is/are likely to affect the health of his unborn baby.

madam [21]

Bob's wife or health is

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3 years ago

Assume you need to design a hydronic system that can deliver 80,000 Btu/hr. What flow rate of water is required if the temperatu

PolarNik [594]

Answer:

At 10°F change in temperature

Mass flowrate = 1.01 kg/s = 2.227 lbm/s

Volumetric flowrate = 1010 m³/s = 35667.8 ft³/s

At 20°F change in temperature

Mass flowrate = 0.505 kg/s = 1.113 lbm/s

Volumetric flowrate = 505 m³/s = 17833.9 ft³/s

Explanation:

80000 btu/hr = 23445.7 W

P = ṁc(ΔT)

ṁ = MASS flowrate

c = specific heat capacity of water = 4182 J/kg.K,

ΔT = change in temperature = 10°F

To convert, a change of 18°F is equal to a change of 10°C

A change of 10°F = 10×10/18 = 5.556°C = 5.556K

P = ṁc(ΔT)

23445.7 = ṁ(4182 × 5.556)

ṁ = 23445.7/(4182 × 5.556)

ṁ = 1.01 kg/s = 2.227 lbm/s

In volumetric flow rate, Q = density × mass flowrate = 1000 × 1.01 = 1010 m³/s = 35667.8 ft³/s

For a change of 20°F,

ΔT = change in temperature = 20°F

To convert, a change of 18°F is equal to a change of 10°C

A change of 20°F = 20×10/18 = 11.1111°C = 11.111K

P = ṁc(ΔT)

23445.7 = ṁ(4182 × 11.111)

ṁ = 23445.7/(4182 × 11.111)

ṁ = 0.505 kg/s = 1.113 lbm/s

In volumetric flow rate, Q = density × mass flowrate = 1000 × 0.505 = 505 m³/s = 17833.9 ft³/s

Hope this Helps!!!

4 0

4 years ago

In the sum A→+B→=C→, vector A→ has a magnitude of 13.6 m and is angled 40.2° counterclockwise from the +x direction, and vector

il63 [147K]

Answer:

$|B|=27.00425726m$

$\alpha =210.3781372$ °

Explanation:

Let's use the component method of vector addition:

$A_x=13.6cos(40.2)=10.38762599\\A_y=13.6sin(40.2)=8.778224553\\Cx=13.8cos(20.7+180)=-12.90912763\\Cy=13.8sin(20.7+180)=-4.877952844$

Now, we know:

$C_x=A_x+B_x\\\\C_y=A_y+b_y$

So:

$B_x=C_x-A_x=-23.29675362\\B_y=C_y-A_y=-13.6561774$

Now lets calculate the magnitude of the vector B:

$|B|=\sqrt{(B_x)^{2} +(B_y)^{2} }=27.00425726m$

Finally its angle is given by:

$\alpha =(arctan(\frac{B_y}{B_x}))+180=30.37813438+180=210.3781344$ °

Keep in mind that I added 180 to the angles of C and B to find the real angles measured from the + x axis counter-clock wise.

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3 years ago

How did the invention of movable type change society?

alexdok [17]

The moveable type drastically changed society. Its primary impact was the distribution of knowledge. Since people could now type books, rather than handwriting then, literary works could be shared faster than ever before. This had a massive impact on education.

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3 years ago

if it is true that the net charge in the universe does not change, how is it ever possible to charge an object that was initiall

olga55 [171]

By transferring electrical charges from one object to another

Explanation:

The law of conservation of electric charge states that the total electric charge of the universe is constant, therefore no charge can be created or destroyed, but only transferred.

Indeed, when an object is charged, this is due to the fact that charge carriers (typically electrons) are transferred to/from the object.

Consider an object initially neutral: this means that the object has initially an equal amount of positive charges (protons) and negative charges (electron).

Later, if we remove electrons from the object, then it will remain with an excess of protons: therefore, it will be positively charged. However, the electrons have not disappeared: simply, they have been moved somewhere else (on another object, for example, which will become negatively charged: so, the total net charge will still be zero).

Similarly, if we add electrons to the object, it will become negatively charged: however, the electrons have been removed from another object which is now positively charged, so the net charge still has not changed.

Learn more about electric charges:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

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3 years ago