Answer:
Explanation:
solve the parallel resistances
30||40 and 50||30
17.14285714 and 18.75
total Resistance = 35.89285714
V = IR
9V = I *35.89285714
9V / 35.89285714 = I
0.250746 = I
Now use the resistance across AB
V = 17.14285714 * 0.250746
V = 4.29850
this is the Voltage drop across AB :P
Answer:
sand and air
Explanation:
air is a mix of carbon dioxide and oxygen and sand is a mix of rocks and stuff
The answer is "A. qualitative".
Qualitative Research is essentially exploratory research. It is utilized to pick up a comprehension of fundamental reasons, sentiments, and inspirations. It gives bits of knowledge into the issue or creates thoughts or speculations for potential quantitative research. Qualitative Research is additionally used to reveal drifts in thought and feelings, and jump further into the issue. Qualitative information accumulation strategies change utilizing unstructured or semi-organized methods. Some basic strategies incorporate concentration gatherings (amass talks), singular meetings, and cooperation/perceptions. The example estimate is commonly little, and respondents are chosen to satisfy a given share.
I'll just find out the path difference between the waves at the starting point. At infinity, the path difference will be zero because the observer will be infinitely far away from both. As the observer goes farther, the path difference keeps reducing till it reaches zero as the observer reaches infinity.
<span>Path difference at starting point = Distance from lower speaker - Distance from upper speaker = √((3)² + (2.5)²) - 2.5 = 1.405 m </span>
<span>Now to find wavelength. </span>
<span>Speed of sound in air at 20 degrees C = 343 m/s </span>
<span>Wavelength = 343 / 686 = 0.5 m </span>
<span>Destructive interference occurs when path difference = (2n + 1)λ/2 where n is an integer. </span>
<span>Maximum n possible can be found by, </span>
<span>(2n + 1)λ/2 < 1.405 </span>
<span>(2n + 1) < (1.4)(2) / (0.5) </span>
<span>2n < 5.6 - 1 </span>
<span>2n < 4.6 </span>
<span>n < 2.3 </span>
<span>So, we have 3 values of n, 0, 1 and 2. </span>
<span>Path differences are, λ/2, 3λ/2 and 5λ/2 which have values 0.25 m , 0.75 m and 1.25 m </span>
<span>But the question asks for distance from starting point. (sheesh!!) </span>
<span>Lets say the observer walked x distance. </span>
<span>Path difference = √((3)² + (2.5 + x)²) - (2.5 + x) </span>
<span>Equate this expression to the values obtained above to get the different values of x. </span>
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