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Irina-Kira [14]

4 years ago

8

What are aerial plants

1 answer:

Alex_Xolod [135]4 years ago

7 0

Answer: Aerial plants is plants that lives in air or wind the wind serves as the water of the plants. Most aerial plants are found in tropical and equatorial regions of the world. In evergreen rain forests, the foliage is so thick that some plants have evolved aerial roots to allow them to absorb more sunlight. The development of aerial roots is

thus an evolutionary process.Aerial roots are often thick and spread around the parent tree. The Banyan tree can have several aerial roots as it gets older.

Explanation:

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Based on Schaffer's arguments in "The Value of a Sherpa Life," choose the statement

Tju [1.3M]

Answer:

Sherpas do work that is much more meaningful than the work other climbers do.

Explanation:

3 0

3 years ago

What are some resources used to generate electricity in energy stations?

Setler79 [48]

-- Coal
-- Oil
-- Natural gas
-- Falling water
-- Sunlight
-- Nuclear fission of Uranium

3 0

3 years ago

. A bathysphere used for deep-sea exploration has a radius of 1.50 m and a mass of 1.20 104 kg. To dive, this submarine takes on

dangina [55]

Answer:

Explanation:

Given that,

Bathysphere radius

r = 1.5m

Mass of bathysphere

M = 1.2 × 10⁴ kg

Constant speed of descending.

v = 1.2m/s

Resistive force

Fr = 1100N upward direction

Density of water

ρ = 1.03 × 10³kg/m³

The volume of the bathysphere can be calculated using

V = 4πr³ / 3

V = 4π × 1.5³ / 3

V = 14.14 m³

The Bouyant force can be calculated using

Fb = ρgV

Fb = 1.03 × 10³ × 9.81 × 14.14

Fb = 142,846.18 N

Buoyant force is acting upward

Weight of the bathysphere

W = mg

W = 1.2 × 10⁴ × 9.81

W = 117,720 N

Weight is acting downward

The net positive buoyant using resolving

Fb+ = Fb — W

Fb+ = 142,846.18 — 117,720

Fb+ = 25,126.18 N

The force acting downward is the weight of the submarine and it is equal to the positive buoyant force and the resistive force

W = Fb+ + Fr

W = 25,126.18 + 1100

W = 26,226.18

mg = 26,226.18

m = 26,226.18 / 9.81

m = 2673.4kg

Mass of submarine is 2673.4kg

8 0

3 years ago

A rubbit gets down from a rump which its /\x=0.85m in 0.5s, The rubbit's mass is 2kg, what is the net Force?

Ira Lisetskai [31]

Answer: 13.6 N

Explanation:

The equation of motion for the rabbit is:

$\Delta x=V_{ox}t+\frac{1}{2}a_{x}t^{2}$ (1)

Where:

$\Delta x=0.85 m$ is the distance traveled by the rabbit

$V_{ox}=0 m/s$ is the rabbit's initial velocity, assuming it started from rest

$t=0.5 s$ is the time

$a_{x}$ is the acceleration

Isolating $a_{x}$ :

$a_{x}=\frac{2 \Delta x}{t^{2}}$ (2)

$a_{x}=\frac{2 (0.85 m)}{(0.5)^{2}}$ (3)

$a_{x}=6.8 m/s^{2}$ (4)

On the other hand, the force $F_{x}$ is given by:

$F_{x}=m.a_{x}$ (5)

Where $m=2 kg$ is the mass of the rabbit

Substituting (4) in (5):

$F_{x}=(2 kg)(6.8 m/s^{2})$ (6)

Finally:

$F_{x}=13.6 N$

6 0

3 years ago

What is 1 + 2 -3 +5 - 10

e-lub [12.9K]

-5 is the correct answer for this!

5 0

3 years ago