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Sindrei [870]
3 years ago
11

A block of ice is floating in a cup of water. It is 0.5 cm above the water surface and its length

Physics
1 answer:
Lapatulllka [165]3 years ago
6 0

Answer:

Let the volume of the cube be V and the fraction of cube outside water be f.

Thus, volume of ice inside water = volume of water displaced =(1−f)V

Under equilibrium,

Weight of ice = Weight of water displaced

⟹Vρ

ice

g=(1−f)Vρ

water

g

⟹(1−f)=

10

9

⟹f=

10

1

Thus, the percentage of volume outside water =10%

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<h3>In a consistent electric field, is force constant?</h3>

Similar to an ordinary object in the uniform gravitational field near the Earth's surface, a charged item in a uniform electric field experiences a constant force and consequently experiences a uniform acceleration. The vector cross product of p and E determines the torque's direction.

If the charge is positive, the force either moves in the same direction as E or in the opposite direction (if charge is negative).

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