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elixir [45]
3 years ago
10

a teacher performing a demonstration finds that a piece of cork displaces 23.5 mL of water. the piece of cork has a mass of 5.7g

. what is the density of the cork?
Physics
2 answers:
8090 [49]3 years ago
6 0
D = M/V.... it can be thought of as
D = ♡ with a line through it
............
D = .0057 kg / .0235 L
= .2425531915 kg/L
= .24 kg/L
____ [38]3 years ago
6 0

Explanation:

It is given that,

Mass of piece of cork, m = 5.7 g

Water displaced by the piece of cork, volume of the bar, V=23.5\ mL=23.5\ cm^3

We need to find the density of the platinum bar. The density of any substance is given by :

d=\dfrac{m}{V}

d=\dfrac{5.7\ g}{23.5\ cm^3}

d=0.242\ g/cm^3

So, the density of the platinum bar 0.242\ g/cm^3. Hence, this is the required solution.

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Answer:

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<u>Step 2: Rewrite Equation</u>

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<u>Step 3: Differentiate</u>

<em>Differentiate the new area formula with respect to time.</em>

  1. Differentiate [Basic Power Rule]:                                                                   \frac{dA}{dt} = 2 \cdot 2w^{2-1}\frac{dw}{dt}
  2. Simplify:                                                                                                           \frac{dA}{dt} = 4w\frac{dw}{dt}

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  1. Substitute:                    \frac{dA}{dt} = 4(300 \ m)(24 \ m/year)
  2. Multiply:                        \frac{dA}{dt} = (1200 \ m)(24 \ m/year)
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