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elixir [45]
3 years ago
10

a teacher performing a demonstration finds that a piece of cork displaces 23.5 mL of water. the piece of cork has a mass of 5.7g

. what is the density of the cork?
Physics
2 answers:
8090 [49]3 years ago
6 0
D = M/V.... it can be thought of as
D = ♡ with a line through it
............
D = .0057 kg / .0235 L
= .2425531915 kg/L
= .24 kg/L
____ [38]3 years ago
6 0

Explanation:

It is given that,

Mass of piece of cork, m = 5.7 g

Water displaced by the piece of cork, volume of the bar, V=23.5\ mL=23.5\ cm^3

We need to find the density of the platinum bar. The density of any substance is given by :

d=\dfrac{m}{V}

d=\dfrac{5.7\ g}{23.5\ cm^3}

d=0.242\ g/cm^3

So, the density of the platinum bar 0.242\ g/cm^3. Hence, this is the required solution.

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Two motorcyclists are riding side-by-side at night and the distance between their center-mounted headlights is 1.40 m. (a) If th
dezoksy [38]

Answer:

θ = 1.591 10⁻² rad

Explanation:

For this exercise we must suppose a criterion when two light sources are considered separated, we use the most common criterion the Rayleigh criterion that establishes that two light sources are separated census the central maximum of one of them coincides with the first minimum of the other source

         

Let's write the diffraction equation for a slit

       a sin θ = m λ

The first minimum occurs for m = 1, also field in these we experience the angles are very small, we can approximate the sin θ = θ

             θ = λ / a

In our case, the pupil is circular, so the system must be solved in polar coordinates, so a numerical constant is introduced.

           θ = 1.22 λ / D

Where D is the diameter of the pupil

 Let's apply this equation to our case

        θ = 1.22 600 10⁻⁹ / 0.460 10⁻²

        θ = 1.591 10⁻² rad

This is the angle separation to solve the two light sources

6 0
3 years ago
A 8.50-kg object is hung from the bottom end of a vertical spring fastened to an overhead beam. The object is set into vertical
SpyIntel [72]

Answer: The force constant of the spring is 116.1N/m

Explanation: Please see the attachments below

5 0
3 years ago
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Need help with these 2 questions ??????!!!!! Hurry this is due soon
Readme [11.4K]

Answer: The first one is A and C

Explanation:

7 0
3 years ago
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The deepest point of the Pacific Ocean is 11,033 m, in the Mariana Trench. What is the water pressure at that point? The density
Goshia [24]

Answer: 1.11 x 10⁸ Pa

Explanation:

At any deep, the absolute pressure is the same for all points located  at the same level, and can be expressed as follows:

p = p₀ + δ. g . h, where p₀ = atmospheric pressure = 101, 325 Pa

Replacing by the values, we get:

p= 101,325 Pa + 1025 Kg/m³ . 9.8 m/s². 11,033 m = 1.11 x 10⁸ Pa.

8 0
3 years ago
A hydrogen atom can be in either of two 1S states, whose energy we'll call 0, either of two 2S states, or any of 6 2P states. Th
Mazyrski [523]

In order to solve this problem we must resort to Boltzmann's theory,

His theory describes how energy levels are populated within atoms. The Boltzmann equation gives ratios of level populations as a function of temperature as follow,

\frac{N_2}{N_1} =\frac{g_2}{g_1}e^{-\frac{\Delta E}{k_B T}}

Where,

g1/g2 are the states (statistical weights)

\Delta E Energy

T temperature

k_B Boltzmann constant

We have all the data, thus replacing,

A) The fraction of H in 2P state at 5900K is,

\frac{N_2}{N_1} = \frac{6}{2} e^{\frac{-10.2(1.6*10^{-19})}{1.38*10^{-23}*5900}}

\frac{N_2}{N_1} = 5.92.10^{-9}

<em>Note that I did the convertion in energy, remember that </em>

1eV = 1.6*10^{-19}J

The fraction of H in 2P state at 5900K is 5.92.10^{-9}

B) The fraction of H in 2P state at 4300K is,

\frac{N_2}{N_1} = \frac{6}{2} e^{\frac{-10.2(1.6*10^{-19})}{1.38*10^{-23}*4300}}

\frac{N_2}{N_1} = 3.41*10^{-12}

The fraction of H in 2P state at 4300K is  3.41*10^{-12}

8 0
3 years ago
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