Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Geometry</u>
- Area of a Rectangle: A = lw
<u>Algebra I</u>
- Exponential Property:

<u>Calculus</u>
Derivatives
Differentiating with respect to time
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Explanation:
<u>Step 1: Define</u>
Area is A = lw
2w = l
w = 300 m

<u>Step 2: Rewrite Equation</u>
- Substitute in <em>l</em>: A = (2w)w
- Multiply: A = 2w²
<u>Step 3: Differentiate</u>
<em>Differentiate the new area formula with respect to time.</em>
- Differentiate [Basic Power Rule]:

- Simplify:

<u>Step 4: Find Rate</u>
<em>Use defined variables</em>
- Substitute:

- Multiply:

- Multiply:

The train travells at he speed of 225 km/2.5h
now
225km=225000m
2.5 hr=150min=9000s
=>avg sp of train is=225000/9000s=25m/s
To solve this problem it is necessary to apply the equations related to the law of Maus.
By the law of Maus we know that

Where,
= Intesity of incident light
I = Intensity of polarized light
With our values we have that
6V/m

Then


Therefore the maximum value of the transmitted E vector is 3V/m