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elixir [45]
3 years ago
10

a teacher performing a demonstration finds that a piece of cork displaces 23.5 mL of water. the piece of cork has a mass of 5.7g

. what is the density of the cork?
Physics
2 answers:
8090 [49]3 years ago
6 0
D = M/V.... it can be thought of as
D = ♡ with a line through it
............
D = .0057 kg / .0235 L
= .2425531915 kg/L
= .24 kg/L
____ [38]3 years ago
6 0

Explanation:

It is given that,

Mass of piece of cork, m = 5.7 g

Water displaced by the piece of cork, volume of the bar, V=23.5\ mL=23.5\ cm^3

We need to find the density of the platinum bar. The density of any substance is given by :

d=\dfrac{m}{V}

d=\dfrac{5.7\ g}{23.5\ cm^3}

d=0.242\ g/cm^3

So, the density of the platinum bar 0.242\ g/cm^3. Hence, this is the required solution.

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A moving object has a kinetic energy of 150 J and a momentum of 25.1 kg·m/s.
PolarNik [594]

Answer:

11.95m/s

Explanation:

A moving object has a kinetic energy of 150 J and a momentum of 25.1 kg·m/s.

a) Find the speed of the object. Answer in units of m

K. E =½mv²

150= ½mv²

Multiply both sides by 2

mv² = 300

Divide both sides by v²

m = 300/v² ..................  Equation 1

Momentum is the product of mass and velocity

Momentum = mv

25.1 = mv

Divide both sides by v

m = 25.1/v ................ Equation 2

Equate equations 1 and 2

300/v² = 25.1/v

Cross multiply

25.1v² = 300v

Multiply v with both sides

25.1v = 300

Divide both sides by 25.1

v = 300/25.1

V = 11.95m/s

I hope this was helpful, please mark as brainliest

8 0
3 years ago
. The formation of carbon dioxide from carbon and oxygen is an example of a <br> reaction
Reika [66]
Photosynthesis maybe
8 0
3 years ago
Read 2 more answers
A sphere of plastic of radius = .100 m is completely immersed in water. The density of the plastic is 600 kg/m3. Since the plast
tekilochka [14]

To solve this problem we need to use the proportional relationships between density, mass and volume, together with Newton's second law.

The force can be described as

F = ma \rightarrow mg

Where,

m = Mass

g = Gravitational acceleration

At the same time the Density can be defined as

\rho = \frac{m}{V} \rightarrow m = \rho V

Where,

m = mass

V = Volume

Replacing the value of the mass at the equation of Force we have,

F = \rho V g

Since the difference between the two forces gives us the total Force then we have to

F_T = F_w - F_p

Where

F_w = Force of the water

F_p= Force of plastic

Therefore with the values for this force we have,

F_T = \rho_w Vg - \rho_p Vg

F_T = Vg(\rho_w - \rho_p)

F_T = (\frac{4}{3} \pi r^3) g(\rho_w - \rho_p)

F_T = (\frac{4}{3} \pi (0.1)^3) (9.8)(1000 - 600)

F_T = 16.412 N

Therefore the tension in the thread is 16.412N

3 0
3 years ago
If you want a charged object to become neutral,then you have to ————-? A.Touch it with a positively charged object B.Touch it wi
JulsSmile [24]
A) Touch it with a positively charged object
6 0
3 years ago
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A 0.10- kg ball is thrown straight up into the air with
mezya [45]

Answer:(a)0,(b)1.061 kg-m/s

Explanation:

Given

mass of ball is 0.10 kg

Initial speed is 15 m/s

Maximum height reached by ball is h

v^2-u^2=2as

final velocity =0

-\left ( 15\right )^2=-2\times 9.81\times s

s=\frac{15^2}{2\times 9.81}=11.467 m

thus momentum of ball at maximum height is 0 as velocity is zero

For halfway to maximum height

v^2-u^2=2as_0

where s_0=\frac{11.467}{2}

s_0=5.73 m

v^2=15^2-2\times 9.81\times 5.73

v=10.61 m/s

Thus its momentum is

mv=0.10\times 10.61=1.061 kg-m/s

3 0
3 years ago
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