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elixir [45]
3 years ago
10

a teacher performing a demonstration finds that a piece of cork displaces 23.5 mL of water. the piece of cork has a mass of 5.7g

. what is the density of the cork?
Physics
2 answers:
8090 [49]3 years ago
6 0
D = M/V.... it can be thought of as
D = ♡ with a line through it
............
D = .0057 kg / .0235 L
= .2425531915 kg/L
= .24 kg/L
____ [38]3 years ago
6 0

Explanation:

It is given that,

Mass of piece of cork, m = 5.7 g

Water displaced by the piece of cork, volume of the bar, V=23.5\ mL=23.5\ cm^3

We need to find the density of the platinum bar. The density of any substance is given by :

d=\dfrac{m}{V}

d=\dfrac{5.7\ g}{23.5\ cm^3}

d=0.242\ g/cm^3

So, the density of the platinum bar 0.242\ g/cm^3. Hence, this is the required solution.

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A robot arm moves so that P travels in a circle about point B, which is not moving. Knowing that P starts from rest, and its spe
algol13

Answer

Acceleration=>10.20mm/s

Explanation

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4 0
3 years ago
Josh starts his sled at the top of a 2.9-m-high hill that has a constant slope of 25∘. After reaching the bottom, he slides acro
algol13

Answer:

S=48.29 m

Explanation:

Given that the height of the hill h = 2.9 m

Coefficient of kinetic friction between his sled and the snow μ = 0.08

Let u be the speed of the skier at the bottom of the hill.

By applying conservation of energy at the top and bottom of the inclined plane we get.

Potential Energy=kinetic Energy

mgh = (1/2) mu²

u² = 2gh

u²=2(9.81)(2.9)

   =56.89

u=7.54 m/s

a = - f / m

a = - μ*m*g / m

a = - μg

From equation of motion

v²- u² = 2 -μ g S

v=0 m/s

-(7.54)²=-2(0.06)(9.81)S

S=48.29 m

3 0
3 years ago
A satellite is in a circular orbit 21000 km above the Earth’s surface; i.e., it moves on a circular path under the influence of
mina [271]

Answer:

(orbital speed of the satellite) V₀ = 3.818 km

Time (t) = 4.5 × 10⁴s

Explanation:

Given that:

The radius of the Earth is 6.37 × 10⁶ m;    &

the acceleration of gravity at the satellite’s altitude is 0.532655 m/s

We can calculate the orbital speed of the satellite by using the formula:

Orbital Speed (V₀) = √(r × g)

radius of the orbit (r) = 21000 km + 6.37 × 10⁶ m

                                  = (2.1 × 10⁷ + 6.37 × 10⁶) m

                                  = 27370000

                                  = 2.737 × 10⁷m

Orbital Speed (V₀) = √(r × g)

Orbital Speed (V₀) = √(2.737 × 10⁷  × 0.532655 )

                              = 3818.215

                              = 3.818 × 10³

                             = 3.818 Km

To find the time it takes to complete one orbit around the Earth; we use the formula:

Time (t) = 2 π × \frac{r}{V_o}

            = 2 × 3.14 × \frac{2.737*10^7}{3.818*10^3}

            = 45019.28

            = 4.5 × 10 ⁴ s

6 0
3 years ago
Dr. james van allen and his group of united states scientists discovered a set of ___________. magnetic equators planets magneti
Fofino [41]

RADIATION BELTS....... I think but it should be radiation belt

3 0
3 years ago
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How many molecules are there in 39 grams of water
Llana [10]

Answer:

39 g H2O contains 1.3 ×1024molecules H2O.

Explanation:

8 0
3 years ago
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