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elixir [45]
3 years ago
10

a teacher performing a demonstration finds that a piece of cork displaces 23.5 mL of water. the piece of cork has a mass of 5.7g

. what is the density of the cork?
Physics
2 answers:
8090 [49]3 years ago
6 0
D = M/V.... it can be thought of as
D = ♡ with a line through it
............
D = .0057 kg / .0235 L
= .2425531915 kg/L
= .24 kg/L
____ [38]3 years ago
6 0

Explanation:

It is given that,

Mass of piece of cork, m = 5.7 g

Water displaced by the piece of cork, volume of the bar, V=23.5\ mL=23.5\ cm^3

We need to find the density of the platinum bar. The density of any substance is given by :

d=\dfrac{m}{V}

d=\dfrac{5.7\ g}{23.5\ cm^3}

d=0.242\ g/cm^3

So, the density of the platinum bar 0.242\ g/cm^3. Hence, this is the required solution.

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A penny rolls along the table for a distance of 1.3 meters. Jackie pushes it 40 centimeters further in the same direction.
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A diver 40 m deep in 10 degrees C fresh water exhales a 1.5 cm diameter bubble.
zzz [600]

Answer:

0.0257259766982 m

Explanation:

P_2 = Atmospheric pressure = 101325 Pa

d_1 = Initial diameter = 1.5 cm

d_2 = Final diameter

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h = Depth = 40 m

The pressure is

P_1=P_2+\rho gh\\\Rightarrow P_1=101325+1000\times 9.81\times 40\\\Rightarrow P_1=493725\ Pa

From ideal gas law we have

\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}\\\Rightarrow \dfrac{P_1\dfrac{4}{3\times8}\pi d_1^3}{T_1}=\dfrac{P_2\dfrac{4}{3\times8}\pi d_2^3}{T_2}\\\Rightarrow \dfrac{P_1d_1^3}{T_1}=\dfrac{P_2d_2^3}{T_2}\\\Rightarrow d_2=(\dfrac{P_1d_1^3T_2}{P_2T_1})^{\dfrac{1}{3}}\\\Rightarrow d_2=(\dfrac{493725\times 0.015^3\times (20+273.15)}{101325\times (10+273.15)})^{\dfrac{1}{3}}\\\Rightarrow d_2=0.0257259766982\ m

The diameter of the bubble is 0.0257259766982 m

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