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vagabundo [1.1K]
3 years ago
12

There are 92 naturally occurring elements. How does this relate to the number of compounds?

Physics
1 answer:
raketka [301]3 years ago
3 0

C) Elements combine in different ways to create many more than 92 compounds.

Explanation:

The number of elements we have relates to the compound formation in that, elements combine in different ways to create many more than 92.

Elements are distinct substances that cannot be split up into simpler substances. Such substances are only made up of one kind of atom.

Compounds are substances that are made up of two or more kinds of atoms joined together in a definite grouping.

  • Several millions of compounds are known because elements can combine in different ways.
  • The number of elements do not increase because new elements are discovered, it is because elements have several ways by they combine.

Learn more:

Chemical reactions brainly.com/question/3953793

#learnwithBrainly

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A beam of monochromatic light is aimed at a slit of width and forms a diffraction pattern. In which case is the width of the cen
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2 years ago
A 37 cm long solenoid, 1.8 cm in diameter, is to produce a 0.50 T magnetic field at its center. If the maximum current is 4.4 A,
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33,458.71 turns

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Given: L = 37 cm = 0.37 m, B= 0.50 T, I = 4.4 A, n= number of turn per meter

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3 years ago
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A ball with a mass of 2000 g is floating on the surface of a pool of water. What is the minimum volume that the ball could have
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Answer:

2000\; {\rm cm^{3}}.

Explanation:

When the ball is placed in this pool of water, part of the ball would be beneath the surface of the pool. The volume of the water that this ball displaced is equal to the volume of the ball that is beneath the water surface.

The buoyancy force on this ball would be equal in magnitude to the weight of water that this ball has displaced.

Let m(\text{ball}) denote the mass of this ball. Let m(\text{water}) denote the mass of water that this ball has displaced.

Let g denote the gravitational field strength. The weight of this ball would be m(\text{ball}) \, g. Likewise, the weight of water displaced would be m(\text{water})\, g.

For this ball to stay afloat, the buoyancy force on this ball should be greater than or equal to the weight of this ball. In other words:

\text{buoyancy} \ge m(\text{ball})\, g.

At the same time, buoyancy is equal in magnitude the the weight of water displaced. Thus:

\text{buoyancy} = m(\text{water}) \, g.

Therefore:

m(\text{water})\, g = \text{buoyancy} \ge m(\text{ball})\, g.

m(\text{water}) \ge m(\text{ball}).

In other words, the mass of water that this ball displaced should be greater than or equal to the mass of of the ball. Let \rho(\text{water}) denote the density of water. The volume of water that this ball should displace would be:

\begin{aligned}V(\text{water}) &= \frac{m(\text{water})}{\rho(\text{water})} \\ &\ge \frac{m(\text{ball}))}{\rho(\text{water})}  \end{aligned}.

Given that m(\text{ball}) = 2000\; {\rm g} while \rho = 1.00\; {\rm g\cdot cm^{-3}}:

\begin{aligned}V(\text{water}) &\ge \frac{m(\text{ball}))}{\rho(\text{water})}  \\ &= \frac{2000\; {\rm g}}{1.00\; {\rm g\cdot cm^{-3}}} \\ &= 2000\; {\rm cm^{3}}\end{aligned}.

In other words, for this ball to stay afloat, at least 2000\; {\rm cm^{3}} of the volume of this ball should be under water. Therefore, the volume of this ball should be at least 2000\; {\rm cm^{3}}\!.

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