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2 years ago

Solve the following system of equations by substitution. y=-1 5x + 7y = -2

Mathematics

1 answer:

Nady [450]2 years ago

7 0

Answer:

(1,-1)

Step-by-step explanation:

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Find the value of the power

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Answer:

Power is the zero at the end of the number like this 56 small 0 at the top right

Step-by-step explanation: Its not just the zero its whatever number is divided by the power it cant go past 50

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2 years ago

Shade the grid to represent the ratio 9/25. Then find a percent equivalent to the given ratio.

anzhelika [568]

Answers and workings in the attachment below.

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3 years ago

What is the equation of the sinusoid shown in the graph?

ololo11 [35]

Answer:

Answer: C

Step-by-step explanation:

The Cosine Function

The graph of a cosine function is a sinusoid that starts at its maximum value of 1 at x=0 and takes x=2π radians to complete a full cycle. The function of the parent cosine function is:

$y=\cos x$

Both the amplitude A and the angular frequency w of a cosine can be modeled by the function

$y=A\cos(\omega x)$

The graph of the cosine function shown in the figure has an amplitude of A=3 and it completes a full cycle at x=π/2, thus:

$\frac{\pi}{2}\omega =2\pi$

Thus:

$\omega = 4$

Therefore, the equation of the sinusoid is:

$y=3\cos (4x)$

Answer: C

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3 years ago

Read 2 more answers

Help please 8. What is mZHTA?

klemol [59]

Answer:

Step-by-step explanation:

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3 years ago

Each of 16 students measured the circumference of a tennis ball by four different methods, which were: A: Estimate the circumfer

almond37 [142]

Answer:

Following are the solution to the given equation:

Step-by-step explanation:

Please find the complete question in the attachment file.

In point a:

$\to \mu=\frac{\sum xi}{n}$

$=22.8$

$\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}$

$=\sqrt{\frac{119.18}{16-1}}\\\\ =\sqrt{\frac{119.18}{15}}\\\\ = \sqrt{7.94533333}\\\\=2.8187$

In point b:

$\to \mu=\frac{\sum xi}{n}$

$=20.6875$

$\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}$

$=\sqrt{\frac{26.3375}{16-1}}\\\\=\sqrt{\frac{26.3375}{15}}\\\\ =\sqrt{1.75583333}\\\\ =1.3251$

In point c:

$\to \mu=\frac{\sum xi}{n}$

$=21$

$\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}$

$=\sqrt{\frac{2.62}{16-1}}\\\\ =\sqrt{\frac{2.62}{15}} \\\\= \sqrt{0.174666667}\\\\=0.4179$

In point d:

$\to \mu=\frac{\sum xi}{n}$

$=20.8375$

$\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}$

$=\sqrt{\frac{8.2975}{16-1}}\\\\ =\sqrt{\frac{8.2975}{15}} \\\\ =\sqrt{0.553166667} \\\\ =0.7438$

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3 years ago