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DanielleElmas [232]
2 years ago
15

Solve for x. X-4 = 8 * 3

Mathematics
1 answer:
Grace [21]2 years ago
5 0

Answer:

The answer is X=28.

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Which expressions are equivalent to (2^5)^-2
Aleonysh [2.5K]
Answer: Choice B) 2^(-10) and 1/1024

------------------------------------------------------

Explanation:

We'll use these two rules
Rule 1: (a^b)^c = a^(b*c)
Rule 2: a^(-b) = 1/(a^b)

Using rule 1 above, we can say
(2^5)^(-2) = 2^(5*(-2)) = 2^(-10)
So 2^(-10) is one of the answers

Now use rule 2 to convert 2^(-10) into...
2^(-10) = 1/(2^10) = 1/1024
so 1/1024 is the other answer
6 0
3 years ago
The bathroom and the living room in a tiny house share a wall. The area of the bathroom is 36 square feet. The area of the livin
jeka94

Answer:

96square feet

Step-by-step explanation:

Given data

Area of bathroom=36 square feet

Area of living room= 60 square feet

Hence the total area of the Bathroom and the living room combined is

= 36+60

=96square feet

7 0
2 years ago
1 2 3 4 5 6 7 8 9 10 TIME REMAINING 54:32 Because the lid of a marker is wider than the marker itself, a set of markers can be p
tia_tia [17]

Answer:

10 Square Inches

Step-by-step explanation:

<u>Trapezoid</u>

Base =12 inches

Height =10 inches

Top side= 10 inches.

Area of a Trapezoid=\frac{1}{2}(a+b)h, $where a and b are the lengths of the base and top respectively$

=\frac{1}{2}(10+12)*10\\=5*22=110 \:Square\:Inches

Area of the Trapezoid=110 Square Inches

<u>Rectangle</u>

Base = 12 inches

Height =10 inches.

Area of a Rectangle=Base X Height

=12 X 10

=120 Square Inches

<u>Difference in Area between the two packages</u>

Difference=Area of Rectangle-Area of Trapezoid

=120-110

=10 Square Inches

5 0
2 years ago
Read 2 more answers
20 years ago, father's age was 5 times his son's age. Now his age is 10 years more than twice his son's present age. Find their
Montano1993 [528]

Step-by-step explanation:

x = father's age now

y = son's age now

x = 2y + 10

x - 20 = 5(y - 20) = 5y - 100

using the first in the second equation :

2y + 10 - 20 = 5y - 100

-10 = 3y - 100

90 = 3y

y = 30

x = 2y + 10 = 2×30 + 10 = 60 + 10 = 70

the father is now 70 years old, the son now 30 years old.

6 0
1 year ago
Derive this with respect to x<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B%281%20%2B%20%20secx%29%20%7D%20" id="Tex
Elenna [48]

~~~~\dfrac{d}{dx} \left(\dfrac{3}{1 + \sec x} \right)\\\\\\=3 \dfrac{d}{dx} \left( \dfrac 1{ 1+ \sec x} \right)\\\\\\=3 \dfrac{d}{dx} (1+ \sec x)^{-1}\\\\\\=3 (-1) (1 + \sec x )^{-1 -1} \dfrac{d}{dx}( 1 + \sec x)\\\\\\=-3(1 + \sec x)^{-2}  ( 0 + \sec x  \tan x)\\\\\\=-\dfrac{3\sec x \tan x}{(1 + \sec x)^2}

8 0
1 year ago
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