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The electrical conductivities of the following 0.100 M solutions were measured in an apparatus that contained a light bulb as th

Rufina [12.5K]

Answer:

Al(NO₃)₃ > KI > HF > CH₃OH

Explanation:

The electrical conductivities of the solutions will depend on the concentration of ions in solution.

Al(NO₃)₃ solution contains 0.1 M of Al³⁺ ions and 0.3 M of NO₃⁻ ions

KI solution contains 0.1 M of K⁺ ions and 0.1 M of I⁻ ions

HF solution contains less than 0.1 M of H⁺ ions and less then 0.1 M of F⁻ ions, because the HF acid will not dissociate completely

CH₃OH practically it does not dissociate, so in the solution will not be electrical conductive (comparative with the other solutions)

The solutions in order of decreasing intensity of the bulb are ranked as following:

Al(NO₃)₃ > KI > HF > CH₃OH

5 0

3 years ago

A sample of gas occupies 40.0 mL at -123°C. What volume does the sample occupy at 27°C if the pressure is held constant? V1T2 =

Brums [2.3K]

Answer:

80mL

Explanation:

Step 1:

Data obtained from the question.

Initial Volume (V1) = 40mL

Initial temperature (T1) = –123°C

Final temperature (T2) = 27°C

Final volume (V2) =..?

Step 2:

Conversion of celsius temperature to Kelvin temperature.

T(K) = T(°C) + 273

Initial temperature (T1) = –123°C =

–123°C + 273 = 150K

Final temperature (T2) = 27°C = 27°C + 273 = 300K

Step 3:

Determination of the final volume.

This can be obtained as follow:

V1/T1 = V2/T2

Initial Volume (V1) = 40mL

Initial temperature (T1) = 150K

Final temperature (T2) = 300

Final volume (V2) =..?

V1/T1 = V2 /T2

40/150 = V2 /300

Cross multiply

150 x V2 = 40 x 300

Divide both side by 150

V2 = (40 x 300) /150

V2 = 80mL

Therefore, the new volume of the gas is 80mL

6 0

3 years ago

Acetylene gas (C2H2) is used in welding torches. When it reacts with oxygen, it produces

Vikki [24]

Mass C₂H₂ needed : 22.165 g

<h3>Further explanation</h3>

Reaction

2C₂H₂+ 5O₂ ⇒ 4CO₂ + 2H₂O

75.0 grams of CO₂ , mol CO₂ (MW=44 g/mol) :

$\tt \dfrac{75}{44}=1.705$

mol C₂H₂ :

$\tt \dfrac{2}{4}\times 1.705=0.8525$

mass C₂H₂ (MW=26 g/mol) :

$\tt 0.8525\times 26=22.165~g$

8 0

3 years ago

Explain how energy is conserved between this reaction and the and surrounding environment C3H8+4O2->3CO2+4H2O+ heat (-2218.6)

alukav5142 [94]

Answer:

The heat of formation = Heat of formation of the products - Heat of formation of the reactants

= -2323 + 104 = -2219 ≈ -2218.6 kJ/mol.

Explanation:

The law of conservation of energy states that the total energy is constant in any process. Energy may change in form or be transferred from one system to another, but the total remains the same

The heat of formation of C₃H₈ is 3C + 4 H₂ → C₃H₈ $\Delta H^{\circ}_f$ -104 kJ/mol

The heat of formation of O₂ is O₂ (g) → O₂ (g) $\Delta H^{\circ}_f$ 0 kJ/mol

The heat of formation of H₂O is H₂(g) + 1/2 O₂→ H₂O (g) $\Delta H^{\circ}_f$ -286kJ/mol

The heat of formation of CO₂ is C (s) + O₂ (g) → CO₂ (g) $\Delta H^{\circ}_f$ -393 kJ/mol

Therefore, in the given reaction we have;

C₃H₈ + 4 O₂ → 3 CO₂ + 4 H₂O

The heat of formation = Heat of formation of the products - Heat of formation of the reactants

The heat of formation = 3 × (-393) + 4 × (-286) - (-104) = -2219 ≈ -2218.6 kJ/mol.

5 0

3 years ago

Select the correct answer. Which two factors does the power of a machine depend on? A. work and distance B. force and distance C

Furkat [3]

Answer:

C. Work and time

Explanation:

Power is the rate work is done, so this would involve how long it would take to do a certain amount of Work and it is also the measure of the transfer of energy over a period of time.

The formula for power is:

$P = \dfrac{W}{t}$

Where:

P = Power

W = Work

t = time

7 0

3 years ago