To do this, you would first add together the molar mass of all involved elements, to find how many grams are in a mole of Cu(OH)2. Keep in mind, the molar mass is equal to the atomic mass of an element in grams. For example the molar mass of copper (Cu) would be 63.55 (with 2 sig. figs.)
Therefore, now we add together the mass of all elements involved.
Cu: (63.55)+O2(15.99x2=31.98)+H2(1.01x2=2.02)
63.55+31.98+2.02= 97.55g per mole of Cu(OH)2.
Now, divide what we have by how much it takes to get a mole of the stuff.
68.1/97.55= 0.698mol Cu(OH)2
<span>A 18 M solution of an acid that ionizes only slightly in solution would be termed
concentrated and weak. The concentration of the acid is high. The acid which dissociates partially in water is a weak acid.
</span><span>Calculate the [H^+] for the aqueous solution in which [OH^-] is 1 x10^-9. Is this solution acidic, basic or neutral. To determine [H+] use:
1x10^-14 = [OH-][H+]
solve for [H+]
[H+] = 1x10^-14/1x10^-9
= 1x10^-5</span>
Explanation:
The given data is as follows.
Pressure of moist hydrogen gas = 1.018 atm
Pressure of water vapor = 
= 0.0421 atm
Formula to calculate the pressure of dry hydrogen gas is as follows.
Pressure of 
gas = 
Now, putting the given values into the above formula as follows.
Pressure of gas =
= 1.018 atm - 0.0421 atm
= 0.976 atm
Therefore, we can conclude that partial pressure of hydrogen gas in the given sample is 0.976 atm.
Answer:
This is the conversion factor, we have to use:
44 g / 1mol
Explanation:
The reaction for the methane combustion is:
CH₄ + 2O₂ → CO₂ + 2H₂O
First of all we use this conversion factor to determine the moles of methane, we used.
50.6 g . 1 mol / 16 g = 3.16 mol
So ratio is 1:1, then 3.16 mol of methane will produce 3.16 moles of CO₂
To calculate the grams of produced dioxide:
3.16 mol . 44 g / 1mol = 139.04 g
