Answer:
full octets live in noble gas world so you need to be whatever your charge is away from there in steps on the periodic table so s-1 is the one that falls short as it is 2 moves away from Ar which is its closest Noble gas
Explanation:
<em> </em><em>5</em><em>-</em><em>b</em><em>r</em><em>o</em><em>m</em><em>o</em><em>-</em><em>1</em><em>.</em><em>1</em><em>.</em><em>1</em><em>-</em><em>t</em><em>r</em><em>i</em><em>c</em><em>h</em><em>l</em><em>o</em><em>r</em><em>o</em><em>-</em><em>5</em><em>e</em><em>t</em><em>h</em><em>l</em><em>y</em><em>-</em><em>2</em><em>.</em><em>3</em>
methyl-heptane
When a warm air mass and a cold air mass meet and cant move its called "stationary front"
Positive ions are positive because they have lost electrons.
(A)-This sounds accurate, but is actually not true. When an atom loses an electron and forms a positive ion, there will be less negative charge from the electrons to attract the positively charged nucleus. Losing electrons will actually decrease the attraction between the electrons and the nucleus.
(B)-This is true in some cases, but not all. If, for example, sodium were to lose an electron, it would drop down to having its largest orbital being in the second energy level, and would decrease in size. If magnesium were to lose an electron, it would still have one electron in the third energy level, so it wouldn't drop down an energy level.
(C) and (D)-Not sure where these answers even came from.
The actual reason behind the radius of a positive ion being smaller than the radius of its neutral atom is that the repulsive force between the electrons themselves is decreased, causing them to move closer together.