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grigory [225]
3 years ago
12

What is the oxidation state of S in HSO4^2-? (A.P.E.X)

Chemistry
1 answer:
BlackZzzverrR [31]3 years ago
7 0

I think there is a typo because I've never seen HSO4 2- before in my life. It should be HSO4-. For that, H is 1+ and each Oxygen is 2-0 totaling 8-. So the oxidation state of sulfur +1 - 8 = 7

So the oxidation state of sulfur is +6

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Convert 26.02 x 1023 molecules of C2H8 to grams. Round your answer to the hundredths place.
aliina [53]

Answer:

x= 138.24 g

Explanation:

We use the avogradro's number

6.023 x 10^23 molecules -> 1 mol C2H8

26.02 x 10^23 molecules -> x

x= (26.02 x 10^23 molecules  * 1 mol C2H8 )/6.023 x 10^23 molecules

x= 4.32 mol C2H8

1 mol C2H8     -> 32 g

4.32 mol C2H8 -> x

x= (4.32 mol C2H8 * 32 g)/ 1 mol C2H8

x= 138.24 g

4 0
3 years ago
Consider an oxygen-concentration cell consisting of two zinc electrodes. One is immersed in a water solution with a low oxygen c
blsea [12.9K]

Answer:

(a) The anode electrode which comprises the zinc electrode being placed in a water solution with low oxygen concentration.

(b) Cathodic reaction is: O_{2} + 2H_{2}O + 4e^{-} ⇒ 4OH^{-}

Anodic reaction is: Zn ⇒Zn^{2+} + 2e^{-}

Explanation:

In the given problem, we have an oxygen-concentration cell consisting of two zinc electrodes. One is immersed in a water solution with a low oxygen concentration and the other in a water solution with a high oxygen concentration. The zinc electrodes are connected by an external copper wire.

(a) Which electrode will corrode?

The electrode that will corrode is the anode electrode which comprises the zinc electrode being placed in a water solution with low oxygen concentration.

(b) Write half-cell reactions for the anodic reaction and the cathodic reaction.

Cathodic reaction is: O_{2} + 2H_{2}O + 4e^{-} ⇒ 4OH^{-}

Anodic reaction is: Zn ⇒Zn^{2+} + 2e^{-}

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4 years ago
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bearhunter [10]

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6 0
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What are the components of the formula for finding force?
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