968 ÷ 38 help me now plzzz

Mathematics

1 answer:

ankoles [38]2 years ago

6 0

Answer:

25.47368421

Step-by-step explanation:

just use a calculator

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How would you solve this? help.

Eddi Din [679]

Answer:

<em>Center: (3,3)</em>

<em>Radius: </em> $2\sqrt{5}$ <em />

Step-by-step explanation:

<u>Midpoint and Distance Between two Points</u>

Given two points A(x1,y1) and B(x2,y2), the midpoint M(xm,ym) between A and B has the following coordinates:

$\displaystyle x_m=\frac{x_1+x_2}{2}$

$\displaystyle y_m=\frac{y_1+y_2}{2}$

The distance between both points is given by:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Point (5,7) is the center of circle A, and point (1,-1) is the center of the circle B. Given both points belong to circle C, the center of C must be the midpoint from A to B:

$\displaystyle x_m=\frac{5+1}{2}=\frac{6}{2}=3$

$\displaystyle y_m=\frac{7-1}{2}=\frac{6}{2}=3$

Center of circle C: (3,3)

The radius of C is half the distance between A and B:

$d=\sqrt{(1-5)^2+(-1-7)^2}$

$d=\sqrt{16+64}=\sqrt{80}=\sqrt{16*5}=4\sqrt{5}$

The radius of C is d/2:

$r =4\sqrt{5}/2 = 2\sqrt{5}$

Center: (3,3)

Radius: $2\sqrt{5}$

8 0

3 years ago

Find the angle between the vectors u=i-9j and v=8i+5j

Katyanochek1 [597]

Answer: $\cos^{-1} \left(\frac{-37}{\sqrt{7298}} \right) \approx 115.665^{\circ}$

Step-by-step explanation:

$u \cdot v=(1)(8)+(-9)(5)=-37\\\\|u|=\sqrt{1^{2}+(-9)^{2}}=\sqrt{82}\\\\|v|=\sqrt{8^{2}+5^{2}}=\sqrt{89}\\\\\cos \theta=\frac{-37}{\sqrt{82}\sqrt{89}}\\\\\theta=\cos^{-1} \left(\frac{-37}{\sqrt{82}\sqrt{89}} \right)\\\\\theta=\boxed{\cos^{-1} \left(\frac{-37}{\sqrt{7298}} \right) \approx 115.665^{\circ}}$