All categories

3 years ago

If k=(a,b,c) and B=(10,5) find b×k

Mathematics

2 answers:

diamong [38]3 years ago

4 0

Answer:

nose eee e e e e e e e e

Step-by-step explanation:

qhhabbejeheh0

Aleks [24]3 years ago

4 0

Answer:

IS BIGGNER

Step-by-step explanation:

ABC WINNER ZILONG

ANSWERRR BY✏

SUGIONO REALL☠

You might be interested in

You are at an pear picking farm and they allow you to pick up to 50 pears a day. Today, you have already picked 14 pears. Which

Olenka [21]

Answer:

p + 14 ≤ 50

Step-by-step explanation:

what you pick, p , plus the 14 you have, must be less than the 50 allowed.

7 0

4 years ago

A chemist has 100 g of a 15% saline solution that she wants to strengthen to 29%. The percentage P of salt in the solution by ma

Vinil7 [7]

Answer:

D., x= 19.7 or ≈20. g

Step-by-step explanation:

P(x) = [100(15+x)]/(100+x)

When 0 g additional salt is added, x=0. we have

P(0) = [100(15+0)]/(100+0)= 15

x=0, P=15

We can see this point only on the graph D.

P(x) =29 = [100(15+x)]/(100+x)

29 = [100(15+x)]/(100+x)

29(100+x) = 100(15+x)

2900+29x = 1500+100x

2900-1500=100x-29x

1400 = 71x

x ≈ 19.7 g or ≈20. g

From the graph D, we can see that to get 29% we need to add ≈ 20 g of salt.

4 0

3 years ago

Consider two boxes, one containing one black and one white marble, the other, two black and one white marble. A box is selected

valina [46]

Answer:

$\frac{7}{12}$

Step-by-step explanation:

Probability refers to chance of happening of some event.

Conditional probability is the probability of an event A, given that another event B has already occurred.

$B_1,B_2$ denote the two boxes.

In box $B_1$ :

No. of black balls = 1

No. of white balls = 1

In box $B_2$ :

No. of black balls = 2

No. of white balls = 1

Let B, W denote black and white marble.

So, probability that either of the boxes $B_1,B_2$ is chosen is $\frac{1}{2}$

Probability that a black ball is chosen from box $B_1$ = $\frac{1}{2}$

Probability that a black ball is chosen from box $B_2=\frac{2}{3}$

To find:probability that the marble is black

Solution:

Probability that the marble is black = $\frac{1}{2}(\frac{1}{2} )+\frac{1}{2}(\frac{2}{3})=\frac{1}{4}+\frac{1}{3}=\frac{7}{12}$

6 0

3 years ago

Explain how you can find the side length of a rectangular prism if you are given the volume in the two other measurements. Does

Kruka [31]

Let's remember that V = lwh. If you are given two other measurements, you can multiply those two and divide V by that quantity to solve for the missing variable. Same process no matter the value:)

6 0

3 years ago

A school has 200 students and spends $40 on supplies for each student. The principal expects the number of students to increase

Xelga [282]

Answer:

$\mathbf{S(t)=200(\frac{105}{100})^{x}}$

$\mathbf{A(t)=40(\frac{98}{100})^{x}}$

$\mathbf{E(t)=S(t) \cdot A(t)=200(\frac{105}{100})^{x} \cdot 40(\frac{98}{100})^{x}=8000(\frac{10290}{10000})^{x}}$

Step-by-step explanation:

<h3>The predicted number of students over time, S(t) </h3>

Rate of increment is 5% per year.

A function 'S(t)' which gives the number of students in school after 't' years.

S(0) means the initial year when the number of students is 200.

S(0) = 200

S(1) means the number of students in school after one year when the number increased by 5% than previous year which is 200.

S(1) = 200 + 5% of 200 = $200+\frac{5}{100}\time200$ = $200(1+\frac{5}{100})$ = $200(\frac{105}{100})$

S(2) means the number of students in school after two year when the number increased by 5% than previous year which is S(1)

S(2) = S(1) + 5% of S(1) = $\textrm{S}(1)(\frac{105}{100})$ = $200(\frac{105}{100})(\frac{105}{100})$ = $200(\frac{105}{100})^{2}$

Similarly $\mathbf{S(x)=200(\frac{105}{100})^{x}}$

<h3>The predicted amount spent per student over time, A(t) </h3>

Rate of decrements is 2% per year.

A function 'A(t)' which gives the amount spend on each student in school after 't' years.

A(0) means the initial year when the number of students is 40.

A(0) = 40

A(1) means the amount spend on each student in school after one year when the amount decreased by 2% than previous year which is 40.

A(1) = 40 + 2% of 40 = $40-\frac{2}{100}\time40$ = $40(1-\frac{2}{100})$ = $40(\frac{98}{100})$

A(2) means the amount spend on each student in school after two year when the amount decreased by 2% than previous year which is A(1)

A(2) = A(1) + 2% of A(1) = $\textrm{A}(1)(\frac{98}{100})$ = $40(\frac{98}{100})(\frac{98}{100})$ = $40(\frac{98}{100})^{2}$

Similarly $\mathbf{A(x)=40(\frac{98}{100})^{x}}$

<h3>The predicted total expense for supplies each year over time, E(t)</h3>

Total expense = (number of students) × (amount spend on each student)

E(t) = S(t) × A(t)

$\mathbf{E(t)=S(t) \cdot A(t)=200(\frac{105}{100})^{x} \cdot 40(\frac{98}{100})^{x}=8000(\frac{10290}{10000})^{x}}$

$\mathbf{E(t)=8000(\frac{10290}{10000})^{x}}$

(NOTE : The value of x in all the above equation is between zero(0) to ten(10).)

6 0

3 years ago

Read 2 more answers

If k=(a,b,c) and B=(10,5) find b×k​

If k=(a,b,c) and B=(10,5) find b×k