Answer:
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Step-by-step explanation:
Answer:
<h2>5 units</h2>
Step-by-step explanation:
A right angled triangle is a triangle that has one of this angles to be 90°. According to the ΔABC, the angle at B is 90°.
Area of a triangle = 1/2 * base * height
According to the diagram shown, the base is BC and the height is AB which is the required side.
Area of the triangle = 1/2 * BC * AB
Given area of the triangle = 10 square units
BC = 4 units
AB is the required length.
Substituting this values into the formula above;
10 = 1/2 * 4 * AB
10 = 2AB
Dividing both sides by 2
2AB/2 = 10/2
AB = 5 units
Hence the length of AB is 5 units.
Answer:
<h3>72 units</h3>
Step-by-step explanation:
Given D,E, and F are collinear points and E is between D and F, then the expression DE + EF = DF.... 1 is true
If DE is six times the length of EF, then;
DE = 6DF
DF = DE/6 .....2
Substitute equation 2 into 1;
DE + EF = DF
DE + DE/6 = DF
find the LCM
(6DE+DE)/6 = DF
cross multiply
6DE+DE = 6DF
7DE = 6DF
Given DF = 84units
7DE = 6(84)
7DE = 504
Divide both sides by 7
7DE/7 = 504/7
DE = 72
Hence the length of segment DE is 72units
according to the topic
5000+1400+1700+2200-5000×80%+1200
=55300-4000+1200
=$52500
Thus we choose option B
B.$52,500
Difference of squares makes (x+3)(x-3)/(x+3)
The x+3’s cancel out
Answer is x-3
