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melamori03 [73]

3 years ago

7

Please help me! Based on the information marked in the diagram, XYZ and ABC must be congruent.

1 answer:

Annette [7]3 years ago

7 0

True

YZ = BC
<Z = <C
XZ = AC

both triangles are congruent by SAS

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All the info is in the pictures

Hunter-Best [27]

Bearing in mind that an absolute value expression is in effect a piece-wise function with two cases, thus

$\bf |-n|=
\begin{cases}
+(-n)\\
-(-n)
\end{cases}\implies 
\begin{cases}
-n\\
n
\end{cases}
\\\\\\
n|-n|=2n\implies 
\begin{cases}
n-n=2n\implies 0=2n\implies &0=n\\
n+n=2n\implies 2n=2n\impliedby &inconsistent
\end{cases}$

6 0

3 years ago

A squre has 12cm length find it's area and perimeter

Alenkinab [10]

Answer:

a=L² is is the formula for the area of square. where L represent the length.

a=(12cm)²

a=144cm²

p=4(L) is the formula for the perimeter of a square. where L represent the length

p=4(12cm)

p=48cm

6 0

3 years ago

Y=–3x + 6y=9 What is the solution to the system of equations? (–21, 9) (9, –21) (–1, 9) (9, –1)

weqwewe [10]

ANSWER

The solution is $(-1,9)$

EXPLANATION

We want to solve the simultaneous equations

$y=-3x+6---(1)$

and

$y=9--(2)$ .

We substitute equation (2) in to equation (1), to obtain

$9=-3x+6$

This has now become a linear equation in a single variable $x$ .

We solve for x by grouping like terms.

$9-6=-3x$

$3=-3x$

We divide through by negative 3 to get;

$-1=x$ .

Hence, the solution is $(-1,9)$

7 0

3 years ago

Read 2 more answers

Using triangle inequality to determine possible lengths of a third side. Can someone help me please?

kotykmax [81]

Answer:

hypotenuse = aprox 18.6

Step-by-step explanation:

a^2 + b^2 = c^2

11^2 + 15^2 = c^2

346 = c^2

square root both sides

c = aprox 18.6

hope that helped!

8 0

3 years ago

When 12 is added to a number the result is 32 less than 3 times a number.<br> What is this number?

neonofarm [45]

X - the number

$x+12=3x-32 \\
x-3x=-32-12 \\
-2x=-44 \\
x=\frac{-44}{-2} \\
x=22$

The number is 22.

7 0

3 years ago

Read 2 more answers