<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E%7B2%7D%20%2B5x%2B3%7D%20%2B2x%5E%7B2%7D%20%2B10x-15%3D0" id="TexFormula1" title

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3 years ago

="\sqrt{x^{2} +5x+3} +2x^{2} +10x-15=0" alt="\sqrt{x^{2} +5x+3} +2x^{2} +10x-15=0" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Anettt [7]3 years ago

8 0

<h3>Factor</h3><h3>√x²+5x+3+2x²+10x-15=0</h3><h3>√x²+2x²+5x+10x+3-15=0</h3><h3>√3x²+15x-12=0</h3><h3>√3x²+(3(5x)+3×-4=0</h3><h3>√3(x²+5x)+3×-4=0</h3><h3>√3(x²+5x-4)=0</h3><h3> </h3>

please mark this answer as brainlist

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Write an equation for a line that is parallel to 2x+5y=15 and passes through the point (-10, 3)

Lyrx [107]

Answer:

The equation of the line is,

$y = - \frac{2}{5} x - 1$

Step-by-step explanation:

First, you have to write it in a form of y = mx + b :

$2x + 5y = 15$

$5y = 15 - 2x$

$y = 3 - \frac{2}{5} x$

$y = - \frac{2}{3} x + 5$

When both lines are parallel to each other, they will have to same gradient value. So the equation of the line is y = (-2/5)x + b. Next, you have to find the value of b by substutituting (-10,3) into the equation :

$y = - \frac{ 2}{5}x + b$