Answer:
v
Step-by-step explanation:
v is 5/-2 on the graph
........,......
Answer:
Hello there! :) This is not a random sample becuase the 54 students are'nt chosen at random.
Step-by-step explanation:
These students are pre-chosen by Mr. Kent, meaning that he could have biased whatever he was interviewing them on. And it does not mention anything like, the first 54 students to leave or the last 54 students to leave. I hope this helps!
Answer:
a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Step-by-step explanation:
I am going to solve this question treating these events as Venn probabilities.
I am going to say that:
Event A: Person has type A blood.
Event B: Person has Rh- factor.
43% of people have type O blood
This means that 
15% of people have Rh- factor
This means that 
52% of people have type O or Rh- factor.
This means that 
a. Find the probability that a person has both type O blood and the Rh- factor.
This is

With what we have

0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b. Find the probability that a person does NOT have both type O blood and the Rh- factor.
1 - 0.06 = 0.94
0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.