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3 years ago

Solve -5/2 +3/4÷1/6 using the order of operations left to right.

Mathematics

1 answer:

musickatia [10]3 years ago

7 0

Answer: -21/2

Concept:

Usually, when doing mathematics operation, it goes by the PEMDAS order:

Parenthesis
Exponent
Multiplication
Division
Addition
Subtraction

However, since the question asks to solve the order of operation from left to right, then we would be doing [addition] --> [Divison]

Solve:

Given

(-5/2) + 3/4 ÷ 1/6

Operate with addition

=(-10/4) + 3/4 ÷ 1/6

=(-7/4) ÷ 1/6

Operate with division

=(-7/4) × 6/1

=-42 / 4

=-21 / 2

Hope this helps!! :)

Please let me know if you have any questions

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3 years ago

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3 years ago

Read 2 more answers

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sweet-ann [11.9K]

Answer:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9$

Step-by-step explanation:

Given

$tan\theta = 3$

Required

Find

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$

Calculate $tan(\theta + \pi) \ and\ tan(\theta+2\pi)$

Using tan rule

$tan(\theta + \pi) = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}$

So:

$tan(\theta + \pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + \pi) = \frac{tan\theta}{1 }$

$tan(\theta + \pi) = \tan\theta$

$tan(\theta+2\pi)$

$tan(\theta + 2\pi) = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}$

$tan(\theta + 2\pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + 2\pi) = \tan\theta$ '

'So:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$ $= tan\theta +tan\theta +tan\theta$

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2 years ago

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slavikrds [6]

Answer:

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