Answer:
0.4 moles of KOH is required to neutralize 0.4 moles of HNO3.
Explanation:
The equation of the reaction is
KOH(aq) + HNO3(aq) ------> KNO3(aq) + H2O(l)
This is a neutralization reaction. A neutralization reaction is a reaction between an acid and a base to form salt and water only.
Having written the balanced chemical reaction equation, we can now solve the prob!em stoichiometrically.
From the balanced reaction equation;
1 mole of KOH is required to neutralize 1 mole of HNO3
Therefore x moles of KOH is required to neutralize 0.4 moles of HNO3
x= 1×0.4/1 = 0.4 moles
Therefore, 0.4 moles of KOH is required to neutralize 0.4 moles of HNO3.
Answer:
this showed that the cathode rays traveled in straight line
ANSWER:
Group 18:
Elements are
-helium(He)
-neon (Ne)
-argon (Ar)
-krypton (Kr)
-xenon (Xe)
-radon (Rn)
-oganesson (Og)
Answer:
202 g/mol
Explanation:
Let's consider the neutralization between a generic monoprotic acid and KOH.
HA + KOH → KA + H₂O
The moles of KOH that reacted are:
0.0164 L × 0.08133 mol/L = 1.33 × 10⁻³ mol
The molar ratio of HA to KOH is 1:1. Then, the moles of HA that reacted are 1.33 × 10⁻³ moles.
1.33 × 10⁻³ moles of HA have a mass of 0.2688 g. The molar mass of the acid is:
0.2688 g/1.33 × 10⁻³ mol = 202 g/mol
