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son4ous [18]
1 year ago
5

A certain first order reaction has a half-life of 54. 3 s. How long will it take (in s) for the reactant concentration to decrea

se from 6. 50 m to 2. 27 m?
Chemistry
1 answer:
Maksim231197 [3]1 year ago
8 0

Answer:

82.4 s

Explanation:

Find the NUMBEr of half lives...then multiply by 54.3

2.27 = 6.5 (1/2)^n

log (2.27/6.5) / log (1/2) = n = 1.52 half lives

1.52 * 54.3 = 82.4 s

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