the large bag is 5/6 lb, the smaller bags will be 1/3 lb, so it should be 5/6 ÷ 1/3
![\bf \cfrac{5}{6}\div \cfrac{1}{3}\implies \cfrac{5}{\underset{2}{~~\begin{matrix} 6 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot \cfrac{~~\begin{matrix} 3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{1}\implies \cfrac{5}{2}\implies 2\frac{1}{2}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B5%7D%7B6%7D%5Cdiv%20%5Ccfrac%7B1%7D%7B3%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B%5Cunderset%7B2%7D%7B~~%5Cbegin%7Bmatrix%7D%206%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%7D%5Ccdot%20%5Ccfrac%7B~~%5Cbegin%7Bmatrix%7D%203%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%7B1%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B2%7D%5Cimplies%202%5Cfrac%7B1%7D%7B2%7D)
There was a 20% decrease
48/60 × 100 = 80%
100 - 80 = 20%
Answer:
Step-by-step explanation:
5
=15.70...
To round a number to the nearest tenth , look at the next place value to the right (the hundredths)which is 0 in this question.
Thus, it will become 15.7
The formula for the area of a trapezoid is A = a+b/2 * h. So just plug in the dimensions.
A = 5 + 3/2 * 5
A = 8/2 * 5
A = 4 * 5
A = 20 units²
I hope this helps love! :)