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Maurinko [17]
2 years ago
15

Please help with question with explanations. Ty.

Mathematics
1 answer:
earnstyle [38]2 years ago
4 0

Answer:

last option is correct answer

Step-by-step explanation:

perimeter = 2(l + w) \\  = 2( \frac{5x + 10}{2x + 5}  +  \frac{x - 2}{2x + 5} ) \\  = 2( \frac{5x + 10 + x - 2}{2x + 5} ) \\  = 2( \frac{6x + 8}{2x + 5} ) \\  =  \frac{12x + 16}{2x + 16}

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Someone help me with 12 I don’t understand stand this question someone please help me with work shown
allochka39001 [22]
2x+8+ 120= 180
Combine like terms so 8+120=128

2x+8+ 120= 180
2x+128=180
-128=-128 ( to both side)
2x= 52 You divide now
2x/2= 52/2
x= 26
There is your answer :)
5 0
3 years ago
Solve
Strike441 [17]

Answer:

x=±\sqrt{15/2}

Step-by-step explanation:

8 0
3 years ago
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An above-ground swimming pool in the shape of a cylinder has a diameter of 18 feet and a height of 4.5 feet. If the pool is fill
laila [671]

The volume of a cylinder is

                                   (pi) (radius²) (height) .

Radius = 1/2 diameter.
Radius of this pool = (1/2) (18 ft) = 9 ft

The pool is a cylinder with height of 4.5 feet. 
The water in it is also a cylinder, but only 4 ft high.

Volume of the water =

             (pi) x (radius²) x (height)

         =  (pi)  x  (9 ft)²  x  (4 ft)

         =  (pi)  x  (81 ft²)  x  (4 ft)

         =  (pi)  x  (324 ft³)  =  1,017.9 ft³ .

7 0
3 years ago
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Jethro is planting flowers in his garden. He wants the ratio of tulips to roses to be 2 to 1. Jethro wants to plant a total of 1
attashe74 [19]

Given:

Ratio of tulips to roses = 2:1

Total number of flowers = 18

To find:

The number of tulips.

Solution:

Let the number of tulips and roses are 2x and x respectively.

According to the question,

2x+x=18

3x=18

Divide both sides by 3.

x=\dfrac{18}{3}

x=6

Now,

Number of tulips =2(6)

                           =12

Therefore, the number of tulips is 12.

7 0
3 years ago
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castortr0y [4]
4 squared+ 12 squared= c squared
16+144=160
Square root 160

so your answer would be 12.6
8 0
3 years ago
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