Draw two lines that connect at one point. label where they connect w and the other two ends j
Answer:
4050 sq. feet.
Step-by-step explanation:
Fencing is done on three sides of the rectangular area.
Given that there are 180 feet of fence available.
Then 2L + W = 180 ........(1), where L = length and W = width, of the rectangular plot.
Now, the area of the plot is given by A = LW
Now, from equation (1), we ger A = L (180 - 2L) ..... (2)
Then differentiating with respect to L in the both sides we get,
{Since condition for Area to be maximum is
}
⇒ L = 45 feet.
Now, from equation (2), we have
square feet.
Given that the function f(x)=1/2x-6 was replaced with f(x+k)=1/2x-4, then the value of k we be as follows:
f(x)=1/2x-6
replacing x1=x+k
f(x+k)=1/2(x+k)-6
equating the above to 1/2x-4 we shall have:
1/2(x+k)-6=1/2x-4
simplifying we obtain:
1/2x+1/2k=1/2x-4
1/2k=-4
hence
k=-8
Answer:radius =10 units
Step-by-step explanation:
Given
Equation of circle is given by
![(x-13.4)^2+(y+2.6)^2=100\quad \ldots(i)](https://tex.z-dn.net/?f=%28x-13.4%29%5E2%2B%28y%2B2.6%29%5E2%3D100%5Cquad%20%5Cldots%28i%29)
Now general equation of circle with center
with radius
is given by
![(x-h)^2+(y-k)^2=r^2\quad \ldots(ii)](https://tex.z-dn.net/?f=%28x-h%29%5E2%2B%28y-k%29%5E2%3Dr%5E2%5Cquad%20%5Cldots%28ii%29)
Comparing
and
we get
![h=13.4](https://tex.z-dn.net/?f=h%3D13.4)
![k=-2.6](https://tex.z-dn.net/?f=k%3D-2.6)
![r=10](https://tex.z-dn.net/?f=r%3D10)
Thus center is ![(13.4,-2.6)](https://tex.z-dn.net/?f=%2813.4%2C-2.6%29)
and radius ![r =10\ units](https://tex.z-dn.net/?f=r%20%3D10%5C%20units)
Side GF^2 = 144 -100
Side GF^2 = 44
Side GF = 2*sqrt(11)
Side GF = 6.6332
Perimeter = 6.6 + 10 + 12
Perimeter = 28.6
Answer is 29 units