The naturally occurring isotopes of Li are Li-6 of mass 6.015121 amu and Li-7 of mass 7.016003 amu. The atomic mass of Li is 6.9409 amu, the percent abundance can be calculated using the following relation.
Atomic mass=m(Li-6 )×%(Li-6 )+m(Li-7 )×%(Li-7 )
Let the percent abundance of Li-6 be X thus, that of Li-7 will be 1-X, putting the values,
Or,
Or,
X=0.075
Thus, 
Thus, percent abundance of Li-6 is 0.075 or 7.5 % and that of Li-7 is 0.925 or 92.5%.
<h3>
Answer:</h3>
2Fe(HCO₃)₃ → Fe₂(CO₃)₃ + 3H₂O + 3CO₂
<h3>
Explanation:</h3>
- A decomposition reaction is one in which a large compound is broken down into smaller compounds or individual elements.
- The decomposition reaction Iron (iii) hydrogen carbonate yield iron (iii) carbonate, water and carbon dioxide.
Fe(HCO₃)₃ → Fe₂(CO₃)₃ + H₂O + CO₂
- A balanced equation is the one in which the number of atoms of each element are equal on both side of the equation.
- Therefore; the balanced equation for the decomposition of Iron (iii) hydrogen carbonate is given by;
2Fe(HCO₃)₃ → Fe₂(CO₃)₃ + 3H₂O + 3CO₂
Answer:
a) 1,737 kJ
b) -1,93 kJ
Explanation:
The standard free energy change (ΔG) can be determined using:
ΔG = -nFE
a) For the reaction:
Fumarate²⁻ + CoQH₂ ⇄ succinate²⁻ + CoQ
The transferred electrons are 2, As E=-0,009V:
ΔG = -2×96,5kJ/molV×-0,009V
<em>ΔG = 1,737 kJ</em>
b) For the reaction:
cytc1 (Fe²⁺) + cytc (Fe³⁺) ⇄ cytc1 (Fe³⁺) + cytc (Fe²⁺)
The transferred electron is n=1 and E=0,02V:
ΔG = -1×96,5kJ/molV×0,02V
<em>ΔG = -1,93 kJ</em>
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I hope it helps!
A molecule consisting of 100 amino acids has a molar mass
of 10,000 amu. The answer is letter A.
The role of the enzyme is to speed up biochemical
reactions. The answer is letter A. it does not take part in the reaction.
Sodium Chloride or NaCl is a ionic bond
