Q = 5637 J

C =4.814 J/KgºC

Temperature : 45.5ºC - 20.9º C = 24.6ºC

Q = m x C x T

5637 = m x 4.814 x 24.6

5637 = m x 118.4244

m = 5637 / 118.4244

m = 47.60 g

hope this helps!

4 0

3 years ago

An aqueous solution of hydrobromic acid is standardized by titration with a 0.164 M solution of calcium hydroxide. If 14.9 mL of

Arada [10]

Answer:

The molarity of hydrobromic acid is 0.182 M

Explanation:

Step 1: Data given

Molarity of Calcium hydroxide = 0.164 M

Volume of calcium hydroxide = 14.9 mL = 0.0149 L

Volume of HBr = 26.9 mL = 0.0269 L

Step 2: The balanced equation

Ca(OH)2 + 2HBr →CaBr2 + 2H2O

Step 3: Calculate molarity of HBr

b*Ca*Va = a*Cb*Vb

⇒b = the coefficient of HBr = 2

⇒Ca = the molarity of Ca(OH)2 = 0.164 M

⇒Va = the volume of ca(OH)2 = 0.0149 L

⇒a= the coefficient of Ca(OH)2 = 1

⇒Cb = the molarity of HBr = TO BE DETERMINED

⇒Vb = the volume of HBr = 0.0269 L

2*0.164 * 0.0149 = 1*Cb*0.0269

Cb = 0.182 M

The molarity of hydrobromic acid is 0.182 M

6 0

4 years ago

A 9.75 L 9.75 L container holds a mixture of two gases at 41 ° C. 41 °C. The partial pressures of gas A and gas B, respectively,

Triss [41]

Answer:

The total pressure P = 1.642 atm

Explanation:

From the dalton's law

Total pressure of the mixture is

$P = P_{A} + P_{B} + P_{C}$ ----- (1)

$P_A = 0.419$ atm

$P_B = 0.589$ atm

$P_C = \frac{nRT}{V}$

n = 0.24 mole

R = $0.0821$ $\frac{L.Atm}{K.mol}$

T = 41 °c = 314 K

$P_C = \frac{(0.24)(0.0821)(314)}{9.75}$

$P_C$ = 0.634 atm

From equation (1)

P = 0.419 + 0.589 + 0.634

P = 1.642 atm

Thus the total pressure P = 1.642 atm

3 0

3 years ago

Answer plz need help asap

LenaWriter [7]

it is Charles Hamilton Houstoun<span />

6 0

4 years ago