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frutty [35]
2 years ago
7

Why the noble gases are found in small amounts in the earth's atmosphere?

Chemistry
1 answer:
777dan777 [17]2 years ago
5 0

Answer:

They have completely filled outermost shell

Explanation:

The noble gases are the rarest and occur in trace amounts in the atmosphere because they have completely filled outermost and this makes them unreactive with other elements.

Elements become abundant as they combine with other species to form compounds.

Noble gases on the other hand have a high level of stability and do not readily combine with other species.

Some of these gases are :

        Helium

        Neon

        Argon

        Krypton

        Xenon

       Radon

They have very high ionization energy and very low electron affinity and so will not readily react.

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Answer:Rule 1: The oxidation number of an element in its free (uncombined) state is zero — for example, Al(s) or Zn(s). This is also true for elements found in nature as diatomic (two-atom) elements

Explanation:

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A first-order reaction has a half-life of 20.0 minutes. Starting with 1.00 x 10^20 molecules
blsea [12.9K]

Answer:

E

Explanation:

100 minutes is   5 half lives  ( 100 min/20 min/half life)

         = (1/2 )^5

1 x 10^20    *    (1/2)^5 =   3.125 x10^18   molecules

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1 year ago
After a rain a puddle of water remains on a sidewalk after a day o sunshine the puddle is gone which process is most responsible
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3 years ago
A 500.0-mL buffer solution is 0.100 M in HNO2 and 0.150 M in KNO2. Determine if each addition would exceed the capacity of the b
likoan [24]

Answer:

no one additions exceed the capacity of the buffer

Explanation:

given

Volume buffer = 500.0 mL = 0.5 L

mol HNO₂ = 0.5 L × 0.100 mol/L = 0.05 mol HNO₂

mol NO₂⁻ = 0.5 L × 0.150 mol/L = 0.075 mol NO₂⁻

solution

we know when any base more than 0.05 (HNO2) than exceed buffer capacity

and when any base more than 0.075 (KNO2) than exceed buffer capacity

when we add 250 mg NaOH (0.250 g)

than molar mass NaOH =40 g/mol

and mol NaOH = 0.250 g ÷ 40g/mol

mol NaOH  = 0.00625 mol

0.00625 mol NaOH will be neutralized by 0.00625 mol HNO₂

so it would not exceed the capacity of the buffer.

and

when we add 350 mg KOH (0.350 g)

than molar mass KOH =56.10 g

and mol KOH = 0.350 g ÷ 56.10 g/mol

mol KOH = 0.0062 mol

here also capacity of the buffer will not be exceeded

and

now we  add 1.25 g HBr

than molar mass HBr = 80.91 g/mol

and mol HBr = 1.25 g  ÷ 80.91 g/mol

mol HBr = 0.015 mol

0.015 mol Hbr will neutralize 0.015 mol NO₂⁻  

so the capacity will not be exceeded.

and

we add 1.35 g HI  

molar mass HI = 127.91 g/mol

so mol HI = 1.35 g ÷ 127.91 g/mol

mol HI = 0.011 mol

capacity of the buffer will not be exceed

3 0
2 years ago
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