The line that is being constructed in the series of diagrams provided is perpendicular.
Total height of lumber, H = 10 1/2 feet = 21/2 feet .
Height of side panel, h = 5 2/3 feet = 17/3 feet .
Now,
Extra lumber required, L = 2 × Height of side panel - Total height of lumber
![L=[2\times (\dfrac{17}{3})]-\dfrac{21}{2}\\\\L = \dfrac{5}{6}\ feet](https://tex.z-dn.net/?f=L%3D%5B2%5Ctimes%20%28%5Cdfrac%7B17%7D%7B3%7D%29%5D-%5Cdfrac%7B21%7D%7B2%7D%5C%5C%5C%5CL%20%3D%20%5Cdfrac%7B5%7D%7B6%7D%5C%20feet)
Therefore, extra lumber required is
feet.
Hence, this is the required solution.
9.66 - you just multiple 6 by 1.61
J is correct. the scale is balanced, so x = 1. there are 9 1’s on the right, and 6 1’s on the left. there are 3 more blocks, and they would have to each be 1.
Answer:
3y √21 + 2 y√15
Step-by-step explanation:
To simply, we open up the bracket
We have this as;
√(189y^2) + √60y
= 3y √21 + 2 y√15