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Marianna [84]
2 years ago
10

Pls help with this question

Mathematics
2 answers:
serious [3.7K]2 years ago
7 0

Try this

(x^2 + x - 12) + (x^2 - 8x + 16)

2y - 1

√36

i wanted to help you! :)

murzikaleks [220]2 years ago
7 0

Answer:

\frac{3}{3} = 1   (everything basically cancels)

Step-by-step explanation:

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Can somebody help me on 23 and 24, it’s geometry
Luda [366]

Question 23:

x = 4

DE = 44

Question 24:

x = 25

SE = 28

Step-by-step explanation:

As RS is the perpendicular bisector of DE, it will divide DE in two equal parts DS and SE

<u>Question number 23:</u>

Given

DS = 3x+10

SE = 6x-2

As the two segments are equal:

DS = SE\\3x+10 = 6x-2

Subtracting 10 from both sides

3x+10-10 = 6x-2-10\\3x = 6x-12

subtracting 6x from both sides

3x -6x = 6x-6x-12\\-3x = -12

Dividing both sides by -3

\frac{-3x}{-3} = \frac{-12}{-3}\\x = 4

Now

DS = 3x+10\\= 3(4)+10\\= 12+10\\=22

And

SE = 6x-2\\= 6(4)-2\\= 24 - 2\\=22\\DE = DS+SE\\= 22+22\\=44

<u>Question No 24:</u>

Given

DS = x+3

DE = 56

We know that:

DS = \frac{1}{2}DE\\x+3 = \frac{56}{2}\\x + 3 = 28\\x = 28-3\\x = 25

So

DS = 25+3 = 28

As DS is 28, SE will also be 28

Hence,

Question 23:

x = 4

DE = 44

Question 24:

x = 25

SE = 28

Keywords: Bisector, Line segment

Learn more about line segments at:

  • brainly.com/question/629998
  • brainly.com/question/6208262

#LearnwithBrainly

4 0
3 years ago
How do i solve (3c^2d^4) ^3 x (2c^5d^8)^3?
vredina [299]

Answer:

216c^{21}d^{36}

Step-by-step explanation:

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(3c^2)^3 (d^4)^3 * (2c^5)^3 (d^8)^3

27c^6 d^{12} * 8c^{15} d^{24}

216c^{21}d^{36}

Hope this helps!

7 0
1 year ago
What is three and one third divided by two and one third
Mkey [24]
The correct answer is 10/7 or 1 3/7. Hope this helps.
3 0
2 years ago
Read 2 more answers
complete the square of the following quadratic x^2 14x 9=0 what value is added to both sides of the equation?
aleksley [76]
9 is added to both sides of the equation then you would combine like terms 
8 0
3 years ago
Which statement about the value of x is true?
mylen [45]
X can always be used a 1 .
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3 years ago
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