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marissa [1.9K]
3 years ago
11

Please help me I’m stuck on this! first best answer gets brainliest

Mathematics
1 answer:
klio [65]3 years ago
6 0

Answer:

  1. we are told there are 8 letters, and each letter between A-H is 8 total unique letter
  2. So 8! is going to be the outcome.
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PLEASE HELP THIS IS TIMED<br> WHAT IS THE FOLLOWING SUM FIRST ONE IS QUESTION THE REST ARE CHOICES
murzikaleks [220]
\sqrt[3]{125x^{10}y^{13}}+\sqrt[3]{27x^{10}y^{13}}\\\\\sqrt[3]{125*x^{3}*x^{3}*x^{3}*x*y^{3}*y^{3}*y^{3}*y^{3}*y}+\sqrt[3]{27*x^{3}*x^{3}*x^{3}*x*y^{3}*y^{3}*y^{3}*y^{3}*y}\\\\\\\sqrt[3]{125}\sqrt[3]{x^{3}}\sqrt[3]{x^{3}}\sqrt[3]{x^{3}}\sqrt[3]{x}\sqrt[3]{y^{3}}\sqrt[3]{y^{3}}\sqrt[3]{y^{3}}\sqrt[3]{y^{3}}\sqrt[3]{y}+\sqrt[3]{27}\sqrt[3]{x^{3}}\sqrt[3]{x^{3}}\sqrt[3]{x^{3}}\sqrt[3]{x}\sqrt[3]{y^{3}}\sqrt[3]{y^{3}}\sqrt[3]{y^{3}}\sqrt[3]{y^{3}}\sqrt[3]{y}\\\\\\5*x*x*x*\sqrt[3]{x}y*y*y*y*\sqrt[3]{y}+3*x*x*x*\sqrt[3]{x}*y*y*y*y*\sqrt[3]{y}\\\\5x^{3}\sqrt[3]{x}y^{4}\sqrt[3]{y}+3x^{3}\sqrt[3]{x}y^{4}\sqrt[3]{y}\\\\5x^{3}y^{4}\sqrt[3]{x}\sqrt[3]{y}+3x^{3}y^{4}\sqrt[3]{x}\sqrt[3]{y}\\\\8x^{3}y^{4}\sqrt[3]{x}\sqrt[3]{y}\\\\8x^{3}y^{4}\sqrt[3]{xy}
5 0
3 years ago
A triangle has an area of 36 cm². The base and height are scaled by a factor of 5.
Dafna1 [17]
The area of a triangle in terms of height and base is A = 1/2*base*height

Suppose base = 6 cm and height = 12 cm. Then, A = 1/2*6*12 = 36 cm2.

If the base and height are scales by a factor of 5, b= 30 cm and h = 60 cm. Then, A = 1/2*30*60 = 900 cm2.

Thus the area of the resulting triangle is scaled by a factor of 25, which is 900 cm2.

6 0
3 years ago
Please help ASAP, thank you and have a good night/day❤️
wolverine [178]

Answer:

1. 6 (3)^2 = 54 ft ^2

2. 6 (2)^2 = 24 ft ^2

3. 54+ 24 = 78 ft^2

5 0
3 years ago
Each of six jars contains the same number of candies. Alice moves half of the candies from the first jar to the second jar. Then
tino4ka555 [31]

Answer:

The number of candies in the sixth jar is 42.

Step-by-step explanation:

Assume that there are <em>x</em> number of candies in each of the six jars.

⇒ After Alice moves half of the candies from the first jar to the second jar, the number of candies in the second jar is:

\text{Number of candies in the 2nd jar}=x+\fracx}{2}=\frac{3}{2}x

⇒ After Boris moves half of the candies from the second jar to the third jar, the number of candies in the third jar is:

\text{Number of candies in the 3rd jar}=x+\frac{3x}{4}=\frac{7}{4}x

⇒ After Clara moves half of the candies from the third jar to the fourth jar, the number of candies in the fourth jar is:

\text{Number of candies in the 4th jar}=x+\frac{7x}{4}=\frac{15}{8}x

⇒ After Dara moves half of the candies from the fourth jar to the fifth jar, the number of candies in the fifth jar is:

\text{Number of candies in the 5th jar}=x+\frac{15x}{16}=\frac{31}{16}x

⇒ After Ed moves half of the candies from the fifth jar to the sixth jar, the number of candies in the sixth jar is:

\text{Number of candies in the 6th jar}=x+\frac{31x}{32}=\frac{63}{32}x

Now, it is provided that at the end, 30 candies are in the fourth jar.

Compute the value of <em>x</em> as follows:

\text{Number of candies in the 4th jar}=40\\\\\frac{15}{8}x=40\\\\x=\frac{40\times 8}{15}\\\\x=\frac{64}{3}

Compute the number of candies in the sixth jar as follows:

\text{Number of candies in the 6th jar}=\frac{63}{32}x\\

                                                    =\frac{63}{32}\times\frac{64}{3}\\\\=21\times2\\\\=42

Thus, the number of candies in the sixth jar is 42.

4 0
3 years ago
I'll mark u as brainliest pls help with these 2 questions ​
aev [14]

Answer:

3, 10

Step-by-step explanation:

1.

5x-1=14 ->

5x=15 ->

x=3.

2.

15+3x=45 ->

3x=45-15=30 ->

3x=30 ->

x=10.

Hope that help! :)

5 0
2 years ago
Read 2 more answers
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