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RUDIKE [14]
3 years ago
11

Activity paper to answer

Mathematics
1 answer:
PIT_PIT [208]3 years ago
5 0

Answer:

1.

a) 5cm

b) 16cm

c) 25cm

d) 124cm

2.

a) 4m

b) 6m

c) 10m

d) 26m

3.

a) 2km

b) 4km

c) 11km

d) 28km

Step-by-step explanation:

When you have a number and it tells you to round it to the nearest cm (m, km etc.), it means you just have to make it a whole number (integer) instead of a decimal by rounding it up or down.

To tell whether you round up or down, you look at the number after the decimal place and if it is under 5, you round down but if it is 5-9 you round up.

For example,

If we had 20.3 (not one of the questions) you would round it down to 20 because the 3 after the decimal place is smaller than 5.

However, if we had 24.7 you would have to round it up because the 7 is from 5-9.

Hope this helps :)

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 You need to subtract the two fractions because the denominators are already the same.

When subtracting fractions, you leave the denominator and regularly subtract the numerator.

Your answer will be 2/8 which equals 1/4th 

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You would have to make a point at 6/3 and go down one and to the left 7... then your answer would be -1/2 sooo D=-1 hope this helps
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3 years ago
Which table represents a linear function?​
Andrew [12]

Answer:

The first table is the only table representing a linear function.

Step-by-step explanation:

<em>" You can tell if a table is linear by looking at how X and Y change. If, as X increases by 1, Y increases by a constant rate, then a table is linear. You can find the constant rate by finding the first difference. This table is linear."</em>

<em />

<em />

<em />

<em />

<em>P.S.</em>

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<em>( thanks to G00GLE for the anwers, hat's off to the internet :^) </em>

8 0
3 years ago
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Identify the interval on which the quadratic function is positive.
Alenkasestr [34]

Answer:

\textsf{1. \quad Solution:  $1 < x < 4$,\quad  Interval notation:  $(1, 4)$}

\textsf{2. \quad Solution:  $-2 < x < 4$,\quad  Interval notation:  $(-2, 4)$}

Step-by-step explanation:

<h3><u>Question 1</u></h3>

The intervals on which a <u>quadratic function</u> is positive are those intervals where the function is above the x-axis, i.e. where y > 0.

The zeros of the <u>quadratic function</u> are the points at which the parabola crosses the x-axis.  

As the given <u>quadratic function</u> has a negative leading coefficient, the parabola opens downwards.   Therefore, the interval on which y > 0 is between the zeros.

To find the zeros of the given <u>quadratic function</u>, substitute y = 0 and factor:

\begin{aligned}y&= 0\\\implies -7x^2+35x-28& = 0\\-7(x^2-5x+4)& = 0\\x^2-5x+4& = 0\\x^2-x-4x+4& = 0\\x(x-1)-4(x-1)&= 0\\(x-1)(x-4)& = 0\end{aligned}

Apply the <u>zero-product property</u>:

\implies x-1=0 \implies x=1

\implies x-4=0 \implies x=4

Therefore, the interval on which the function is positive is:

  • Solution:  1 < x < 4
  • Interval notation:  (1, 4)

<h3><u>Question 2</u></h3>

The intervals on which a <u>quadratic function</u> is negative are those intervals where the function is below the x-axis, i.e. where y < 0.

The zeros of the <u>quadratic function</u> are the points at which the parabola crosses the x-axis.  

As the given <u>quadratic function</u> has a positive leading coefficient, the parabola opens upwards.   Therefore, the interval on which y < 0 is between the zeros.

To find the zeros of the given <u>quadratic function</u>, substitute y = 0 and factor:

\begin{aligned}y&= 0\\\implies 2x^2-4x-16& = 0\\2(x^2-2x-8)& = 0\\x^2-2x-8& = 0\\x^2-4x+2-8& = 0\\x(x-4)+2(x-4)&= 0\\(x+2)(x-4)& = 0\end{aligned}

Apply the <u>zero-product property</u>:

\implies x+2=0 \implies x=-2

\implies x-4=0 \implies x=4

Therefore, the interval on which the function is negative is:

  • Solution:  -2 < x < 4
  • Interval notation:  (-2, 4)
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Step-by-step explanation:

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