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2 years ago

Which value of j makes (5 + 3)j = 48 a true statement?

Mathematics

1 answer:

fomenos2 years ago

6 0

You're going to add the numbers I the parenthesis, and then divide that on both sides to isolate and solve for j.

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13/2 divided by 3/4

Juliette [100K]

Answer: 26/3

Step-by-step explanation: When dividing by a fraction, we can change

the division sign to multiplication and flip the second fraction.

So 13/2 ÷ 3/4 means the same thing as 13/2 · 4/3.

So when dividing by a fraction, we can just multiply

by the reciprocal of that fraction or that fraction flipped.

Next we cross-cancel.

4 and 2 reduce to 2 and 1.

Multiplying across the numerator and denominators we have 26/3.

5 0

3 years ago

On picture day, 3 times as many girls wore dresses rather than pants. If there are 12 girls in the class, how many wore a dress?

katrin2010 [14]

Answer:

Step-by-step explanation:

3 * 12 = 36

if there are 12 girls and 3 times more wore dress then 3 times 12 is 36.

3 0

2 years ago

Read 2 more answers

A 16-ounce package of frozen vegetables costs $2.10. How much would you expect a 12-ounce package to cost?

statuscvo [17]

Hi!

We need to find the cost per ounce.
2.10/16 = 0.13125

It costs 0.13125 per ounce.

Now find the cost of 12 ounces.
12 * 0.13125 = $1.58

The answer is $1.58

Hope this helps! :)
-Peredhel

8 0

3 years ago

Read 2 more answers

Find a polynomial with integer coefficients that satisfies the given conditions. R has degree 4 and zeros 3 − 3i and 2, with 2 a

dolphi86 [110]

Answer:

The required polynomial is $P(x)=x^4-10x^3+46x^2-96x+72$ .

Step-by-step explanation:

If a polynomial has degree n and $c_1,c_2,...,c_n$ are zeroes of the polynomial, then the polynomial is defined as

$P(x)=a(x-c_1)(x-c_2)...(x-x_n)$

It is given that the polynomial R has degree 4 and zeros 3 − 3i and 2. The multiplicity of zero 2 is 2.

According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.

Since 3-3i is zero, therefore 3+3i is also a zero.

Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is

$R(x)=(x-3+3i)(x-3-3i)(x-2)(x-2)$

$R(x)=((x-3)+3i)((x-3)-3i)(x-2)^2$

$R(x)=(x-3)^2-(3i)^2((x-3)-3i)(x-2)^2$ $[a^2-b^2=(a-b)(a+b)]$

$R(x)=(x^2-6x+9-9(i)^2((x-3)-3i)(x-2)^2$

$R(x)=(x^2-6x+18)(x^2-4x+4)$ $[i^2=-1]$

$R(x)=(x^2-6x+18)(x^2-4x+4)$

$R(x)=x^4-10x^3+46x^2-96x+72$

Therefore the required polynomial is $P(x)=x^4-10x^3+46x^2-96x+72$ .

3 0

3 years ago

Need help ... ??????????

DochEvi [55]

Answer:

what is the quistion

Step-by-step explanation:

6 0

3 years ago