1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
S_A_V [24]
2 years ago
7

What is the answer when you evaluate m + p - p2 ÷ 6; use m = 5 and p = 6 ?

Mathematics
1 answer:
Tanya [424]2 years ago
3 0

Answer:

5

Step-by-step explanation:

m + p - p^2 ÷ 6

Let m = 5 and p=6

5 + 6 - 6^2 ÷ 6

Exponents first

5 + 6 - 36 ÷ 6

Then divide

5 + 6 - 6

Then add and subtract from left to right

11-6

5

You might be interested in
Write the equation of the line through (-2,1) and parallel to y= -3x+1
DedPeter [7]
Use point slope equation y-y1=m(x-x1) Remember that a parallel line has the same slope.

y-1= -3(x-(-2))
y-1= -3(x+2)
y-1= -3x-6
y= -3x-5

Final answer: y=-3x-5
7 0
3 years ago
Write quadratic equation whose roots are 1 and -3 and whose leading coefficient is 4
Mila [183]

Answer:

4x^2 + 8x - 12 = 0.

Step-by-step explanation:

We first write it in factor form.

4(x - 1)(x + 3) = 0

4(x^2 + 2x - 3) = 0

4x^2 + 8x - 12 = 0 (answer).

3 0
3 years ago
Read 2 more answers
An object launched straight up at a speed of 29.4 meters per second has a height, h, in meters of h , t seconds after the object
Nostrana [21]

Answer:

h = 44.06 meters (maximum height)

the time the object takes to complete this whole path is 6 seconds, this is why the time at which the object reaches its maximum height will between 0 and 6 seconds

Step-by-step explanation:

To solve this question, we need to first recognize that this is a constant acceleration problem, specifically, it can be thought of as a projectile motion problem.

Recall, the equations of motion:

1) v^2 - v_0^2 = 2a(s - s_0)\\2) s = v_0^2  + \frac{1}{2} at^2\\3) v = v_0 + at

What do we already know?

  • v_0 = 29.4 ms^-1
  • The launch is straight up
  • a = -9.81 ms^-2 this is the gravitational acceleration g
  • s_0 = 0 m, since our reference point is at s = 0, (the ground)

We can use use the Eq(1):

we know that when any object is launched up, at maximum height its velocity is going to be zero, v = 0 ms^-2

v^2 - v_0^2 = 2a(s - s_0)\\0^2 - (29.4)^2 = 2(-9.81)(s- 0)\\s = 44.06 m

this is the maximum height!

Why does t have to between zero and six?

We can answer this using a bit visualization, if you think about the second equation

s = v_0 t - \frac{1}{2}at^2\\ s = 29.4t - 4.905t^2

this is the equation of the whole trajectory that object makes.

and if you solve this by making s = 0, you will get the times at which the object was at the ground. the times will be 0s and 5.99s.

so the amount of time the object takes to go through this whole path is 6 seconds and this why the object will only reach its maximum height in between this time interval.

hope this helps :)

5 0
3 years ago
Find the area of the circle. Round to the nearest square meter. 1, 257m ^ 2 314m ^ 2 897m ^ 2 63m ^ 2
Helga [31]

Answer:

A=πr2

Step-by-step explanation:

3 0
3 years ago
Which of the following is equivalent to the quadratic equation below after completing the square?
Natalka [10]
X^2 + 4x = 0
x^2 + 4x + 4 = 0 + 4
(x + 2)^2 = 4
3 0
3 years ago
Other questions:
  • A 4 cm x 6 cm rectangles it inside a circle with radius of 11 cm what is the radius of the shaded region
    5·1 answer
  • Card 1 has a current balance of $8,312.69 with an APR of 24.16%, and the credit limit on the card is $10,000.
    13·1 answer
  • −2x−x+8 please help cant figure it out
    15·1 answer
  • Estimate then answer the equation.
    5·1 answer
  • Use a special right triangle to write sin 30° as a fraction.
    11·1 answer
  • 0 = 2x2 - 6x + 4<br> What are the solutions to
    6·2 answers
  • Pls help me i’m really not to sure about this question
    6·1 answer
  • The height of the rectangle and the triangle are the same. The base of the triangle is half the base of the rectangle.What is th
    6·1 answer
  • Can someone help me solve this?
    10·1 answer
  • He conic section below is
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!