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Tema [17]
3 years ago
12

4.

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
3 0
<h3>Answer:  6 ounces</h3>

========================================================

Work Shown:

(6 servings)/(4 oz of sauce) = (8 servings)/(x oz of sauce)

6/4 = 8/x

6*x = 4*8

6x = 32

x = 32/6

x = 5.333 approximately

x = 6 we round up despite 5.333 being closer to 5, than it is to 6.

If we went with 5 ounces, then we wouldn't clear the hurdle needed to serve 8 people.

The section below goes over why this is the case in more detail.

---------

6 servings : 4 ounces

6/4 servings : 4/4 ounces

1.5 servings : 1 ounce

So one ounce of sauce gets us 1.5 servings.

If we multiply both sides by 5, then,

1.5 servings : 1 ounce

5*1.5 servings : 5*1 ounce

7.5 servings : 5 ounces

This shows that 5 ounces of sauce will only produce 7.5 servings, which comes up short compared to 8 servings.

If we multiplied both sides by 6, then

1.5 servings : 1 ounce

6*1.5 servings : 6*1 ounce

9 servings : 6 ounces

This shows that 6 ounces of sauce yields 9 servings. We've gone overboard, but it's better to do that than come up short.

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Answer:

The answer is B, your welcome

7 0
3 years ago
Decompose 3/5? I need help !
mr_godi [17]
Hey,

Fractions can be decomposed in many different ways. Decomposing a fraction means breaking it up into smaller parts.

For example you can write 3/5 as 1/5+1/5+1/5 or as 1/5+2/5. 


5 0
4 years ago
Read 2 more answers
PLEASE HELLP I REALY NEED SOME HELP WITH THIS QUESTION
Yuliya22 [10]

It's a summation (sigma) notation.

\sum\limits_{i=1}^n a_i = a_1 + a_2 + ... a_n\\

This expression means the sum of all the terms a_i, where <em>i</em> takes the values from 1 to <em>n</em>.

So <em>i</em> is the index (like a counter) and <em>n</em> is the last value.

In this case:

\sum\limits_{n=1}^6\frac{n}{2n+1} =\frac{1}{2*1+1}+ \frac{2}{2*2+1}+ \frac{3}{2*3+1}+ \frac{4}{2*4+1}+ \frac{5}{2*5+1}+ \frac{6}{2*6+1} \\= \frac{1}{3}+ \frac{2}{5}+\frac{3}{7}+\frac{4}{9}+\frac{5}{11}+\frac{6}{13}=\frac{113623}{45045} \approx 2.522\\\\



3 0
4 years ago
What is the value of d/dx(1/x) at x=6 ?​
sladkih [1.3K]

If you know your derivative rules, then

d/d<em>x</em> [1/<em>x</em>] = -1/<em>x</em> ²

so that when <em>x</em> = 6, the derivative has a value of -1/36.

If you have to use the definition of the derivative, then

d/d<em>x</em> [1/<em>x</em>] = lim {<em>h</em> → 0} (1/(<em>x</em> + <em>h</em>) - 1/<em>x</em>) / <em>h</em>

… = lim {<em>h</em> → 0} (<em>x</em> - (<em>x</em> + <em>h</em>)) / (<em>hx</em> (<em>x</em> + <em>h</em>))

… = lim {<em>h</em> → 0} (-<em>h</em>) / (<em>hx</em> (<em>x</em> + <em>h</em>))

… = lim {<em>h</em> → 0} (-1) / (<em>x</em> (<em>x</em> + <em>h</em>))

… = -1/<em>x</em> ²

and at <em>x</em> = 6, you again get -1/36.

Alternatively, use the definition of the derivative at a point:

d/d<em>x</em> [1/<em>x</em>] (6) = lim {<em>x</em> → 6} (1/<em>x</em> - 1/6) / (<em>x</em> - 6)

… = lim {<em>x</em> → 6} ((6 - <em>x</em>) / (6<em>x</em>)) / (<em>x</em> - 6)

… = lim {<em>x</em> → 6} -(<em>x</em> - 6) / (6<em>x</em> (<em>x</em> - 6))

… = lim {<em>x</em> → 6} (-1) / (6<em>x</em>)

… = -1/36

4 0
3 years ago
-3x-9+15x<br> combine like terms
algol13

Answer:

=12x−9

Step-by-step explanation:

−3x+ −9 +15x

=(−3x+15x) +(−9)

=12x+−9

I hope this helps ^^

3 0
3 years ago
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