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Tema [17]
3 years ago
12

4.

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
3 0
<h3>Answer:  6 ounces</h3>

========================================================

Work Shown:

(6 servings)/(4 oz of sauce) = (8 servings)/(x oz of sauce)

6/4 = 8/x

6*x = 4*8

6x = 32

x = 32/6

x = 5.333 approximately

x = 6 we round up despite 5.333 being closer to 5, than it is to 6.

If we went with 5 ounces, then we wouldn't clear the hurdle needed to serve 8 people.

The section below goes over why this is the case in more detail.

---------

6 servings : 4 ounces

6/4 servings : 4/4 ounces

1.5 servings : 1 ounce

So one ounce of sauce gets us 1.5 servings.

If we multiply both sides by 5, then,

1.5 servings : 1 ounce

5*1.5 servings : 5*1 ounce

7.5 servings : 5 ounces

This shows that 5 ounces of sauce will only produce 7.5 servings, which comes up short compared to 8 servings.

If we multiplied both sides by 6, then

1.5 servings : 1 ounce

6*1.5 servings : 6*1 ounce

9 servings : 6 ounces

This shows that 6 ounces of sauce yields 9 servings. We've gone overboard, but it's better to do that than come up short.

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Step-by-step explanation:

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In order to estimate the difference between the average hourly wages of employees of two branches of a department store, two ind
liberstina [14]

Answer:

Step-by-step explanation:

Hello!

You have two populations of interest and want to compare them. If you define the study variables as:

X₁: average hourly wages of an employee of the Downtown store.

n₁= 25

X[bar]₁= $9

S₁= $2

X₂: average hourly wages of an employee of the North Mall store.

n₂= 20

X[bar]₂= $8

S₂= $1

Both samples taken are independent, assuming that both populations are normal and that their population variances are equal I'll use the Student's-t statistic with a pooled sample variance to calculate the Confidence interval:

95% CI for μ₁ - μ₂

(X[bar]₁-X[bar]₂) ± t_{n_1+n_2-2; 1-\alpha /2} * (Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } )

Sa^2= \frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}

Sa^2= \frac{24*4+19*1}{25+20-2}= 2.67

Sa= 1.64

t_{n_1-n_2-2;1-\alpha /2} = t_{43; 0.975} = 2.017

(9-8)±2.017*(1.64*\sqrt{\frac{1}{25} +\frac{1}{20} } )

[0.007636;1.9923]

I hope it helps!

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