An exponential decay law has the general form: A = Ao * e ^ (-kt) =>
A/Ao = e^(-kt)
Half-life time => A/Ao = 1/2, and t = 4.5 min
=> 1/2 = e^(-k*4.5) => ln(2) = 4.5k => k = ln(2) / 4.5 ≈ 0.154
Now replace the value of k, Ao = 28g and t = 7 min to find how many grams of Thalium-207 will remain:
A = Ao e ^ (-kt) = 28 g * e ^( -0.154 * 7) = 9.5 g
Answer 9.5 g.
I’m sure tbh I finna watch some tvd
Answer:
Ca - 63.546 g
2N - 28.014 g
2O3 - 96 g
Ca(NO3)2 = 187.56 g
187.56 g x 0.75 mol = 140.67 g
Explanation:
Hope this helps
A nuclear reaction<span> in which two or more atomic nuclei come very close and then collide at a very high speed and join to form a new type of atomic nucleus.
Hope this helps :)
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