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noname [10]
2 years ago
13

Na

Chemistry
1 answer:
tensa zangetsu [6.8K]2 years ago
5 0

Answer:

Argon is a noble gas

Hope this helps

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Which of these factors will cause a solid solute to dissolve faster?
Nostrana [21]
I believe the answer you are looking for is the 4th one.
8 0
3 years ago
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HELP
tatiyna

Answer:

Bi (Bismuth)

Ag (Silver)

Li (Lithium)

Explanation:

Xe (Xenon) and I (Iodine) are non-metals. They cannot from a metallic bond because metallic bonds are bonds between metals only.

7 0
2 years ago
The elements in Groups 1 AU) and 7A(17) are all quite reactive. What is a major difference between them?
Yuliya22 [10]

Explanation:

Elements of group 1A are known as alkali metals. Elements of this group are lithium, sodium, potassium, rubidium, cesium, and francium.

All these elements are metals and every element of this group has 1 valence electron. So, in order to attain stability they will readily lose their valence electron.

Hence, elements of group 1A are very reactive.

On the other hand, elements of group 7A are also known as halogen group. Elements of this group are fluorine, chlorine, bromine, iodine, and astatine.

All these elements are non-metals and every element of this group has 7 valence electrons. So, in order to completely fill their octet these elements gain 1 electron from a donor atom.

Therefore, these elements are alo reactive in nature.

But the major difference between elements of group 1A and group 7A is that elements of group 1A are metals but elements of group 7A are non-metals.    

8 0
3 years ago
Be sure to answer all parts. Sulfur dioxide is released in the combustion of coal. Scrubbers use lime slurries of calcium hydrox
scoray [572]

<u>Answer:</u> The balanced chemical equation is written below and \Delta S^o for the reaction is -160.6 J/K

<u>Explanation:</u>

When calcium hydroxide reacts with sulfur dioxide, it leads to the formation of calcium sulfate and water molecule.

The chemical equation for the reaction of calcium hydroxide and sulfur dioxide follows:

Ca(OH)_2(s)+SO_2(g)\rightarrow CaSO_3(s)+H_2O(l)

To calculate the entropy change of the reaction, we use the equation:

\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{products}]-\sum [n\times \Delta S^o_{reactants}]

For the given reaction:

\Delta S^o_{rxn}=[(1\times \Delta S^o_{CaSO_3(s)})+(1\times \Delta S^o_{H_2O(l)})]-[(1\times \Delta S^o_{Ca(OH)_2(s)})+(1\times \Delta S^o_{SO_2(g)})]

Taking the standard entropy change values:

\Delta S^o_{CaSO_3(s)}=101.4Jmol^{-1}K^{-1}\\\Delta S^o_{H_2O(l)}=69.9Jmol^{-1}K^{-1}\\\Delta S^o_{Ca(OH)_2(s)}=83.4Jmol^{-1}K^{-1}\\\Delta S^o_{SO_2(g)}=248.5Jmol^{-1}K^{-1}

Putting values in above equation, we get:

\Delta S^o_{rxn}=[(1\times (101.4))+(1\times (69.9))]-[(1\times (83.4))+(1\times (248.5))]\\\\\Delta S^o_{rxn}=-160.6J/K

Hence, the balanced chemical equation is written above and \Delta S^o for the reaction is -160.6 J/K

3 0
3 years ago
How many of the following are compounds?<br> H2O, N2O4, NaOH, MnO2, HF
lukranit [14]
Im pretty sure all of them are compounds

4 0
3 years ago
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