Question

Answer this question.

Answer 1

Answer:

B) Both functions have a y-intercept of -2.

Step-by-step explanation:

Hi there!

A) Both functions are always increasing.

⇒ False

Let's first take a look at the given equation, $y=3x-2$. This is a linear equation, and it is organized in slope-intercept form: $y=mx+b$. m is the slope and b is the y-intercept. When m is positive, it is always increasing.

In $y=3x-2$, 3 is m, and because it's positive, this line is always increasing on a graph.

However, when we take a look at the given graph, this isn't the case. It is decreasing for values of x below 0 (on the left side of the y-axis).

B) Both functions have a y-intercept of -2.

⇒ True

In the given equation $y=3x-2$, this is true. -2 is the y-intercept.

On the given graph, we can see that the graph intercepts the y-axis at -2, so this is also true for the graph.

C) Both functions are symmetric about the y-axis.

⇒ False

The given graph is symmetric about the y-axis, but the line is not. Any line that would be symmetric about the y-axis would be in the form $y=b$, which isn't the case here with $y=3x-2$. $y=3x-2$ has a slope.

D) Both functions are linear relationships.

⇒ False

Sure, $y=3x-2$ is a linear equation, making it a line, but not the given graph. The graph does not resemble a straight line, so it is not a linear relationship.

I hope this helps!