When the sum of the internal angles of a polygon is 10 right angles, then how
1 answer:
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Answer:
<em>18</em> values for n are possible.
Step-by-step explanation:
Given the quadratic polynomial:
such that:
Roots are positive prime integers and
To find:
How many possible values of are there ?
Solution:
First of all, let us have a look at the sum and product of a quadratic equation.
If the quadratic equation is:
and the roots are: and
Then sum of roots,
Product of roots,
Comparing the given equation with standard equation, we get:
A = 1, B = -m and C = n
Sum of roots,
Product of roots,
We are given that
and
are positive prime integers such that their sum is less than 20.
Let us have a look at some of the positive prime integers:
2, 3, 5, 7, 11, 13, 17, 23, 29, .....
Now, we have to choose two such prime integers from above list such that their sum is less than 20 and the roots can be repetitive as well.
So, possible combinations and possible value of are:
So,as shown above <em>18 values for n are possible.</em>
Answer:
Just substitute 0 instead of f (x),therefore
The answer option is C