Question

Write x2 + 8x + 5 in the form (x+a)2 + b where a and b are integers. a = b=

Answer 1

Answer:

$(x+4)^2 - 11 = 0$

a = 4

b = -11

Step-by-step explanation:

$x^{2} +8x+5$

use the complete the square method:

$x^{2} +8x+5=0\\x^{2} +8x = -5\\\\(x+4)^{2} = x^2 + 8x + 16\\\\x^2 + 8x + 16 = -5 + 16$

we completed the square of x^2 + 8x + ... which is x^2 + 8x + 16 using (x+4)^2

we added 16 to both sides because whatever you do to one side, you have to do to the other:

$x^{2} +8x+16 = 11\\(x+4)^2 = 11\\(x+4)^2 - 11 =0$