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maksim [4K]
3 years ago
12

Sheila conducts an investigation to see how the amount of salt dissolved in water affects the density of the water. Which statem

ent best describes the correct plan for her procedure?
A The density and the amount of water are controls, and the amount of salt and the type of salt are variables.

B The amount of water and the amount of salt are controls, and the type of salt and the density are variables.

C The type of salt and the amount of water are controls, and the amount of salt and the density are variables.

D The type of salt and the density of water are controls, and the amount of salt and the amount of water are variables.
Mathematics
2 answers:
Dovator [93]3 years ago
8 0
C. The controls are things that are the same regardless of what other changes you make in an experiment. The variables are what you change (independent variable) and what you measure (dependent variable).
Assoli18 [71]3 years ago
4 0

Answer:

C - The type of salt and the amount of water are controls, and the amount of salt and the density are variables.

Step-by-step explanation:

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Answer:

y=-\frac{1}{3}x-5

Step-by-step explanation:

Given:

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(x_1,y_1)=(-6,-3)\\(x_2,y_2)=(6,-7)

Now, for a line with two points on it, the slope of the line is given as:

m=\frac{y_2-y_1}{x_2-x_1}

For the points (x_1,y_1)=(-6,-3)\ and\ (x_2,y_2)=(6,-7), slope is:

m=\frac{-7-(-3)}{6-(-6)}\\m=\frac{-7+3}{6+6}\\m=\frac{-4}{12}=-\frac{1}{3}

Now, for a line with slope 'm' and a point (x_1,y_1) on it is given as:

y-y_1=m(x-x_1)

Plug in all the values and determine the equation of the line. This gives,

y-(-3)=-\frac{1}{3}(x-(-6))\\\\y+3=-\frac{1}{3}(x+6)\\\\y+3=-\frac{1}{3}x-\frac{1}{3}\times 6\\\\y+3=-\frac{1}{3}x-2\\\\y=-\frac{1}{3}x-2-3\\\\y=-\frac{1}{3}x-5

Therefore, the equation of the line is:

y=-\frac{1}{3}x-5

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Step-by-step explanation:

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Let the number be x

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