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3 years ago

How are the oscillating magnetic and electric fields of an electromagnetic wave positioned relative to each other?

Physics

1 answer:

Pepsi [2]3 years ago

7 0

Answer:

Electromagnetic waves consist of both electric and magnetic field waves. These waves oscillate in perpendicular planes with respect to each other, and are in phase. The creation of all electromagnetic waves begins with an oscillating charged particle, which creates oscillating electric and magnetic fields.

Explanation:

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4 years ago

A ball is dropped from rest from the top of a building of height h. At the same instant, a second ball is projected vertically u

uranmaximum [27]

Answer:

a) $t = \sqrt{\frac{h}{2g}}$

b) Ball 1 has a greater speed than ball 2 when they are passing.

c) The height is the same for both balls = 3h/4.

Explanation:

a) We can find the time when the two balls meet by equating the distances as follows:

$y = y_{0_{1}} + v_{0_{1}}t - \frac{1}{2}gt^{2}$

Where:

$y_{0_{1}}$ : is the initial height = h

$v_{0_{1}}$ : is the initial speed of ball 1 = 0 (it is dropped from rest)

$y = h - \frac{1}{2}gt^{2}$ (1)

Now, for ball 2 we have:

$y = y_{0_{2}} + v_{0_{2}}t - \frac{1}{2}gt^{2}$

Where:

$y_{0_{2}}$ : is the initial height of ball 2 = 0

$y = v_{0_{2}}t - \frac{1}{2}gt^{2}$ (2)

By equating equation (1) and (2) we have:

$h - \frac{1}{2}gt^{2} = v_{0_{2}}t - \frac{1}{2}gt^{2}$

$t=\frac{h}{v_{0_{2}}}$

Where the initial velocity of the ball 2 is:

$v_{f_{2}}^{2} = v_{0_{2}}^{2} - 2gh$

Since $v_{f_{2}}^{2}$ = 0 at the maximum height (h):

$v_{0_{2}} = \sqrt{2gh}$

Hence, the time when they pass each other is:

$t = \frac{h}{\sqrt{2gh}} = \sqrt{\frac{h}{2g}}$

b) When they are passing the speed of each one is:

For ball 1:

$v_{f_{1}} = - gt = -g*\sqrt{\frac{h}{2g}} = - 0.71\sqrt{gh}$

The minus sign is because ball 1 is going down.

For ball 2:

$v_{f_{2}} = v_{0_{2}} - gt = \sqrt{2gh} - g*\sqrt{\frac{h}{2g}} = (\sqrt{1} - \frac{1}{\sqrt{2}})*\sqrt{gh} = 0.41\sqrt{gh}$

Therefore, taking the magnitude of ball 1 we can see that it has a greater speed than ball 2 when they are passing.

c) The height of the ball is:

For ball 1:

$y_{1} = h - \frac{1}{2}gt^{2} = h - \frac{1}{2}g(\sqrt{\frac{h}{2g}})^{2} = \frac{3}{4}h$

For ball 2:

$y_{2} = v_{0_{2}}t - \frac{1}{2}gt^{2} = \sqrt{2gh}*\sqrt{\frac{h}{2g}} - \frac{1}{2}g(\sqrt{\frac{h}{2g}})^{2} = \frac{3}{4}h$

Then, when they are passing the height is the same for both = 3h/4.

I hope it helps you!

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3 years ago

A uniform linear charge of 2.0 nC/m is distributed along the x axis from x = 0 to x = 3 m. What is the x component of the electr

balu736 [363]

Answer:

The x component of the electric field at y=2m is $E_{x}=17.97\frac{N}{C}$

Explanation:

For a linear charge, using Gauss Law, we get that the Electric field (radial) has the following form

$E=\frac{\lambda}{2\pi\epsilon_{0}r}$

where λ is the charge for longitud unit given in the problem, r is replaced by the y coordinate, and there are two known more data. So

$E=\frac{2*10x^{-9}}{2*2\pi\epsilon_{0}}=17.97\frac{N}{C}$

is the x component of the Electric field at y=2m on the y axis, which is what we wanted to know.

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3 years ago

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dsp73

Answer:

The correct answer is

d. An iron cage

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Explanation:

The theory of the iron was first presented by the sociologist Max Weber in the work The Protestant Ethic and the Spirit of Capitalism.

Here Weber clarified that with the diminishing effect of Protestantism within our social life the capitalist system remained as well as the bureaucratic principles and social structures that came about along with came along with it, such the worldviews and values becomes major controlling factors in socil life which is tantamount to living in a strong house maade of steel

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3 years ago

How are the oscillating magnetic and electric fields of an electromagnetic wave positioned relative to each other?​

How are the oscillating magnetic and electric fields of an electromagnetic wave positioned relative to each other?