Boyle's law<span> is a gas </span>law<span>, stating that the pressure and volume of a gas have an inverse relationship , when temperature is held constant. That is PV = constant. Therefore, (PV)initial = (PV)final. 42x11 = 9x P(final). P(final) = 42x11/9 = 51.34kPa. </span>
<em>Answers:</em>
<em>1. The hot soup will loose the heat and the ice water will gain the heat</em>
- If two jars are insulated inside the insulated box, the heat may not be transferred to outside of the box.
- According to II law of thermodynamics, Heat always flow from high temperature body to low temperature body, with out aid of external energy.
<em>So, from two points, it is concluded that The hot soup will lose heat and the ice water will gain the heat until they reach the thermodynamic equilibrium.</em>
<em>2. The particles in gases are farther apart and move faster </em>
- Particles in the gases are loosely packed (greater distance between particles compared to solids and liquids) and particles collide less often.
<em>Therefore conduction is weak in gases compared to solids and liquids.</em>
<em>3. Heat and milk by conduction; popping popcorn by radiation.</em>
- The heat can transfer from pot to the milk by conduction because they are in contact at boundaries, similarly the pot and the stove are in contact <em>so the conduction transfers heat from pot to the milk. </em>
- In microwave oven there is no direct contact (<em>no conduction</em>) of heat and popcorn, also there is no molecular momentum transfer <em>(means of no convection).</em>
<em>So obviously the heat transfer by radiation occurs in a microwave oven.</em>
The distance traveled per unit time is called speed.
Hope this helps you!
Answer:
300 K
Explanation:
First, we have find the specific heat capacity of the unknown substance.
The heat gained by the substance is given by the formula:
H = m*c*(T2 - T1)
Where m = mass of the substance
c = specific heat capacity
T2 = final temperature
T1 = initial temperature
From the question:
H = 200J
m = 4 kg
T1 = 200K
T2 = 240 K
Therefore:
200 = 4 * c * (240 - 200)
200 = 4 * c * 40
200 = 160 * c
c = 200/160
c = 1.25 J/kgK
The heat capacity of the substance is 1.25 J/kgK.
If 300 J of heat is added, the new heat becomes 500 J.
Hence, we need to find the final temperature, T2, when heat is 500 J.
Using the same formula:
500 = 4 * 1.25 * (T2 - 200)
500 = 5 * (T2 - 200)
100 = T2 - 200
=> T2 = 100 + 200 = 300 K
The new final temperature of the unknown substance is 300K.
Voltage = Current x Resistance
<span>Voltage(?) = 100 x 1.98x10^-4 ohms </span>
<span>Voltage = Current x Resistance </span>
<span>Voltage(?) = 250 x 2.09x10^-4 ohms </span>
<span>Voltage = Current x Resistance </span>
<span>Voltage(?) = 100 x 3.44x10^-4 ohms</span>
