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GenaCL600 [577]
2 years ago
6

A teacher took two latex balloons and blew them up with helium gas to the same size. She took one and labeled it Balloon A and p

laced it in a -15o C freezer. The second one she labeled BALLOON B, and she took it outside and tied it to the railing in the sun on a 30o C day. After a half hour, she had the students measure the circumference of each balloon. Which TWO outcomes do you predict the students will find and why?
Physics
1 answer:
gladu [14]2 years ago
5 0

Answer:

n

Explanation:

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AYOO I NEED HELP plz
oksano4ka [1.4K]

Answer:

1D

2C

3C

4C

5D

6D

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8D

9B

Explanation:

better give me points X﹏X

4 0
3 years ago
Read 2 more answers
Arunner has a speed of 23 m/s. They see the finish line and speed up to 27 m/s. This happens in 5 seconds. If the runner has a m
sp2606 [1]
The answer is 100

Have a great day
6 0
3 years ago
A vertical wire carries current in the upward direction. an electron is traveling parallel to the wire. what is the angle α betw
Luden [163]
Angle α between the velocity of theelectron and the magnetic field of the wire will be 90 degree
7 0
3 years ago
A cannonball is fired at a 45.0° angle and an initial velocity of 670 m/s. Assume no air resistance. What is the vertical compon
elixir [45]

Answer:

<h3>473.8 m/s; 473.8 m/s</h3>

Explanation:

Given the initial velocity U = 670m/s

Horizontal velocity Ux = Ucos theta

Vertical component of the cannon velocity Uy = Usin theta

Given

U = 670m/s

theta = 45°

horizontal component of the cannonball’s velocity = 670 cos 45

horizontal component of the cannonball’s velocity = 670(0.7071)

horizontal component of the cannonball’s velocity = 473.757m/s

Vertical component of the cannonball’s velocity = 670 sin 45

Vertical component of the cannonball’s velocity  = 670 (0.7071)

Vertical component of the cannonball’s velocity  = 473.757m/s

Hence pair of answer is 473.8 m/s; 473.8 m/s

6 0
2 years ago
Ground reaction force acting on carter
mezya [45]
We don't know Carter, and we don't know where he is or what
he's doing, so I'm taking a big chance speculating on an answer.

I'm going to say that if Carter is pretty much just standing there,
or, let's say, lying on the ground taking a nap, then the force of
the ground acting on him is precisely exactly equal to his weight.
8 0
3 years ago
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