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Charra [1.4K]
3 years ago
5

What is the average of 11, 16, 15, 22

Mathematics
1 answer:
Mazyrski [523]3 years ago
6 0

<em><u>The average would be 16.</u></em>

To calculate this, add all the values together then divide that sum by the amount of data values.

11+16+15+22=64

64÷4=16

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Solve the equation for P: 3k=7Q+6p
iren [92.7K]

3k=7Q+6p

Solve for P which means we have to make 'p' alone

3k=7Q+6p\\\\ Add  7Q on both sides \\\\ 3k - 7Q = 7Q - 7Q + 6p\\\\ \left ( 3k - 7Q \right ) = 6p\\\\ Divide both side by 6 to make p alone \\\\ \frac{\left ( 3k - 7Q  \right )}{6} = \frac{6p}{6}\\\\ p = \frac{\left ( 3k - 7Q  \right )}{6}

7 0
3 years ago
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What is V125 in simplest form?
kvv77 [185]

Answer:

5\sqrt{5}

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab} , then

\sqrt{125}

= \sqrt{25(5)}

= \sqrt{25} × \sqrt{5}

= 5\sqrt{5}

6 0
3 years ago
40% of the memberships sold by Gym A were gold memberships.
Aneli [31]

Answer:

a) If both gyms sold 80 total memberships, Gym A sold 12 more gold membership.

Step-by-step explanation:

Here is the complete question: 40% of the memberships sold by Gym A were gold memberships. 25% of the memberships sold by Gym B were gold memberships.  

Which statement must be true?

a) If both gyms sold 80 total memberships, Gym A sold 12 more gold membership.

b) If both gyms sold the same number of memberships, Gym A sold 15 more gold membership.

c) Gym A sold more gold membership than Gym A did.

d) If Gym B sold 50 membership, 25 would be gold memberships.

Given: Gym A have sold 40% gold membership of total membership.

Gym B have sold 25% gold membership of total membership.

Lets take option A first to find if it is true statement.

As per option A, There are total number of membership is 80.

∵ Gym A has sold 40% gold membership.

∴ Gym A gold membership= 40\% \times 80

⇒ Gym A gold membership= \frac{40}{100} \times 80= 32 member.

∴ Gym A gold membership= 32.

Now, Gym B

∵ Gym B has sold 25% gold membership.

∴ Gym B gold membership= 25\% \times 80

⇒ Gym B gold membership= \frac{25}{100} \times 80=20 member.

∴ Gym B gold membership= 20.

Next finding difference gold membership for Gym A and Gym B

32-20= 12 \ membership

Hence, we can say option A is correct as Gym A have sold 12 more gold membership, if total number of membership sold by both Gym is 80.

8 0
3 years ago
To investigate the relationship between amount of sales y (in thousands of dollars) and the amount x (in hundreds of dollars) sp
riadik2000 [5.3K]

Answer:

(A) For each additional hundred dollars spent on advertising, sales are predicted to increase by $2,380.

Step-by-step explanation:

Regression isa statistical equation, denoting relationship between independent (causal) variable(s) & dependent (effected) variable.

y = a <u>+</u> bx

where y = dependent variable, x = dependent variable, a (intercept) = autonomous value of y, b (slope) = change in y due to change in x

Regression equation of independent variable (x) as advertising expenditure & dependent variable (y) sales : y = 24.45 + 2.38x

Sales are in thousands of dollars, advertising expenditure is in hundreds of dollars. So, the interpretations are :

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  • Slope Interpretation :<u> When advertisement expenditure change (rise) by 1 hundred, sales change (rise) by 2.38 thousand i.e</u><u> </u><u>$2380</u>
7 0
3 years ago
Simplify the expression (7a5b6)4 . Please help
8_murik_8 [283]

Answer:

28a 20b 24

Step-by-step explanation:

3 0
3 years ago
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