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allsm [11]
3 years ago
7

Some animals migrate, or seasonally move to a different place. In some bird populations, such as Canada geese, some birds migrat

e and some stay in the same area year-round. Migration can enhance the survival of individuals because it —
exerts a lot of energy.

Chemistry
1 answer:
4vir4ik [10]3 years ago
4 0
The answer to this question is B
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Why does silver gate tarnish on exposed to air
Lelu [443]

Answer:

when silver articles exposed to air silver racts with Sulphur present in the atmosphere and form a black layer of silver sulphide on the surface. copper articles get tarnished by reacting with air and water. due to this, a layer is formed over copper vessels.

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Oil, which is built from the nonmetals hydrogen, carbon, and oxygen:
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Oil consists of many B. Covalent bonds between the nonmetals of Carbon, hydrogen and oxygen.
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If you have 10,000 grams of a substance that decays with a half-life of 14 days, then how much will you have after 56 days?
Crank

Answer: 625 grams

Explanation:

14 goes into 56, 4 times.

10,000÷2=5,000 - first half life

5,000÷2=2,500 - second half life

2,500÷2=1,250 - 3rd half life

1,250÷2= 625 - 4th half life

Note: don't type "grams" after 625, just type "625".

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2 years ago
What element would a metal, like sodium, most likely combine with?
OverLord2011 [107]
The answer you are looking for is "bromine". Hope this helps!
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Problem Page Liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 70. g of
shusha [124]

Answer:

The maximum mass of carbon dioxide that could be produced by the chemical reaction is 70.6gCO_{2}

Explanation:

1. Write down the balanced chemical reaction:

2C_{6}H_{14}_{(l)}+19O_{2}_{(g)}=12CO_{2}_{(g)}+14H_{2}O_{(g)}

2. Find the limiting reagent:

- First calculate the number of moles of hexane and oxygen with the mass given by the problem.

For the hexane:

70.0gC_{6}H_{14}*\frac{1molC_{6}H_{14}}{86.2gC_{6}H_{14}}=0.81molesC_{6}H_{14}

For the oxygen:

81.3gO_{2}*\frac{1molO_{2}}{32.0gO_{2}}=2.54molesO_{2}

- Then divide the number of moles between the stoichiometric coefficient:

For the hexane:

\frac{0.81}{2}=0.41

For the oxygen:

\frac{2.54}{19}=0.13

- As the fraction for the oxygen is the smallest, the oxygen is the limiting reagent.

3. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction:

The calculations must be done with the limiting reagent, that is the oxygen.

81.3gO_{2}*\frac{1molO_{2}}{32gO_{2}}*\frac{12molesCO_{2}}{19molesO_{2}}*\frac{44.0gCO_{2}}{1molCO_{2}}=70.6gCO_{2}

7 0
3 years ago
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