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3 years ago

7

Some animals migrate, or seasonally move to a different place. In some bird populations, such as Canada geese, some birds migrat

e and some stay in the same area year-round. Migration can enhance the survival of individuals because it —
exerts a lot of energy.

1 answer:

4vir4ik [10]3 years ago

4 0

The answer to this question is B

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If 6.02*10^23 molecules of ammonia react with 12.04*10^23 molecules of hydrogen chloride, how many molecules are in the reaction

Helen [10]

Answer:

18.06 × 10²³ molecules

Explanation:

Add the two amounts of molecules together.

6.02 × 10²³ + 12.04 × 10²³ = 18.06 × 10²³

You will have 18.06 × 10²³ molecules in the vessel when the reaction is complete. This is because of the Law of Conservation of Mass. Mass is neither created nor destroyed in chemical reactions. You will have the exact number of molecules in the reaction vessel as you did in the beginning. The types of molecules may change, but the number will stay the same.

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4 years ago

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dlinn [17]

Answer:

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3 years ago

Your dad is working on creating a brick border for the lake in your backyard each brick has a mass of 100 g and a volume of 20 c

wel

Answer:

5000kg/m³

Explanation:

density=mass/volume

d=m/v

d=100/20

=5g/cm³

g/cm³*1000=kg/m³

5g/m³*1000=5000kg/m³

4 0

3 years ago

Read 2 more answers

Solve for Va<br><br>MaVa=MbVb

PolarNik [594]

Answer:

Va = (MbVb)/Ma

Explanation:

Divide both sides by Ma and voila!

8 0

3 years ago

2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2

Harrizon [31]

It can be found that 337.5 g of AgCl formed from 100 g of silver nitrate and 258.4 g of AgCl from 100 g of CaCl₂.

<u>Explanation:</u>

2AgNO₃ + CaCl₂ → 2 AgCl + Ca(NO₃)₂

We have to find the amount of AgCl formed from 100 g of Silver nitrate by writing the expression.

$100 g \text { of } A g N O_{3} \times \frac{2 \text { mol } A g N O_{3}}{169.87 g A g N O_{3}} \times \frac{2 \text { mol } A g C l}{1 \text { mol } A g N O_{3}} \times \frac{143.32 g A g C l}{1 \text { mol } A g C l}$

= 337.5 g AgCl

In the same way, we can find the amount of silver chloride produced from 100 g of Calcium chloride.

It can be found as 258.4 g of AgCl produced from 100 g of Calcium chloride.

4 0

3 years ago