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Lorico [155]
3 years ago
5

For his science project, Chip decided to test how well plants grew with fertilizer. He started off by planting seeds in three di

fferent pots and labeling each of the plants. Plant A had no fertilizer. Plant B had the recommended amount of fertilizer. Plant C had four times the recommended amount of fertilizer. For ten consecutive days he measured the height of each plant in centimeters. The follow ing table shows his results. Which plant grew the most from Day 7 to Day 9?
Mathematics
2 answers:
tino4ka555 [31]3 years ago
8 0

hope it will helps you

ashley here

Korolek [52]3 years ago
7 0

Now in pot experiments the most important point is to have the same number of plants per pot. To achieve this you plant more seeds and then you thin them after emergence to keep the same number of uniform plant per pot.

Now for calculating fertilizer rate of application in pots, you calculate according to soil weigh as you correctly indicated 2.2 M Kg/ha. You don't have to weigh the soil, just use the bulk density to calculate weigh from volume. Forget about space in pot experiment. you will have a lot of problems since pots have different shapes and forms!

Another recommandation mix soil and fertilizers for each treatment for the number of replicate pots. If you are using 5 replicates pot of 2 Kg soil/ pot, mix the fertilizers you want to apply to the 5 pots with 10 Kg of soil and after mixing well (preferably mechanically) distribute the same volume of soil in each one of the 5 pots.

If the amount of fertilizer to apply is small mix with some soil first and mix well before mixing to the whole soil. The idea is to have as much as possible, a uniform distribution.

You might also consider fractionating you nitrogen source if it will be leached.

Now according to the exact aim of your work other method sof fertilizationare possible.

Finally remember that maize is a mycorrhizal plant and this beneficial symbiosis can be influenced by the amount of soluble P you are adding.

Wishing you a lot of success in your work

<h3>hope it's help you </h3><h3>plz mark as brain list.......!!!!!!!!!!!!!!!!</h3>

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sineoko [7]

We have been given an expression \left(\dfrac {6}{17}\right)^{9x}. We are asked to find the value of A when rewrite our given expression as A^{x}.

To solve our given problem, we will use exponent properties.

Using exponent property a^{mn}=(a^m)^n, we can rewrite our given expression as:

\left(\dfrac {6}{17}\right)^{9x}=\left(\left(\dfrac {6}{17}\right)^9\right)^{x}

Now, we will compare our expression with  A^{x}.

Upon comparing \left(\left(\dfrac {6}{17}\right)^9\right)^{x} with A^{x}, we can see that A=\left(\dfrac {6}{17}\right)^9.

Therefore, the value of A is \left(\dfrac {6}{17}\right)^9.

We can further simplify \left(\dfrac {6}{17}\right)^9 as:

\left(\dfrac {6}{17}\right)^9=\frac {6^9}{17^9}=\frac{10077696}{118587876497}

6 0
4 years ago
Jia is skipping a rock across a pond. The sequence {4.2, 3.57, 3.0345, 2.5793, …} describes the height of the rock on each succe
mylen [45]

Answer:

u_n=4.2(0.85)^{n-1}

Step-by-step explanation:

u_1=4.2\\u_2=3.57\\u_3=3.0345\\u_4=2.5793

Geometric formula sequence:   u_n=ar^{(n-1)}

(where a is the first term of the sequence and r is the common ratio)

To find the common ratio, divide one of the terms by the previous term:

r=\frac{u_2}{u_1} =\frac{3.57}{4.2} =0.85

From inspection, a=4.2

Therefore, u_n=4.2(0.85)^{n-1}

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2 years ago
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Find the rate of the changes the first two hours of use after unplugging her laptop ​
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Answer:

Step-by-step explanation:

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3 0
4 years ago
En una hoja de papel cuyo perímetro es de 96 centímetros, se quiere imprimir un volante de manera que el área impresa sea un rec
elixir [45]

Answer:

El perímetro de la región impresa es 72 cm y su área es 288 cm².  

Step-by-step explanation:

1. Tenemos el perímetro de la hoja de papel:

P₁ = 96 cm = 2l₁ + 2a₁  (1)  

Como sabemos el margen superior, inferior, izquierdo y derecho podemos encontrar la relación entre el largo y ancho del rectángulo interno (región impresa) con el largo (l) y ancho (a) del rectángulo externo (hoja de papel):      

l_{2} = l_{1} - (m_{s} + m_{i}) = l_{1} - (3 cm + 2 cm) = l_{1} - 5 cm  (2)            

a_{2} = a_{1} - (m_{d} + m_{iz}) = a_{1} - (2 cm + 5 cm) = a_{1} - 7 cm   (3)    

El perímetro del rectángulo interno es:

P_{2} = 2l_{2} + 2a_{2}    (4)

Introduciendo la ecuación (2) y (3) en (4):

P_{2} = 2l_{2} + 2a_{2} = 2(l_{1} - 5 cm) + 2(a_{1} - 7 cm) = 2l_{1} + 2a_{1} - 10 cm - 14 cm = 96 cm - 24 cm = 72 cm  

Por lo tanto el perímetro del rectángulo interno (región impresa) es 72 cm.

 

2. Ahora para encontrar el área rectángulo interno debemos encontrar el largo y ancho del mismo, sabiendo que:

l_{2} = 2a_{2}     (5)

Introduciendo (5) en (4):

P_{2} = 2l_{2} + 2a_{2} = 2*2a_{2} + 2a_{2} = 6a_{2}

a_{2} = \frac{P_{2}}{6} = \frac{72 cm}{6} = 12 cm

l_{2} = 2a_{2} = 2*12 cm = 24 cm

Entonces el área es:

A_{2} = l_{2}*a_{2} = 12 cm*24 cm = 288 cm^{2}

Por lo tanto el área del rectágulo interno (región impresa) es 288 cm².      

Espero que te sea de utilidad!  

7 0
3 years ago
Who is good at basic math?
quester [9]
Just divide the numbers in their decimal for like 12 would be .12

8 0
3 years ago
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