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3 years ago

Does this picture indicate that < JAC =

Mathematics

1 answer:

xenn [34]3 years ago

8 0

Answer:

Step-by-step explanation:

<JAC = 93

< DBE = 90

The two angles are not equal

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Factor completly 4x^2 +8x -5

DaniilM [7]

∑ Hey, jillianwagler ⊃

Answer:

$\left(2x-1\right)\left(2x+5\right)$

Step-by-step explanation:

║Given info║:

Factor completely: $4x^2 +8x -5$

Solution~:

Breaking the expression~: $\left(4x^2-2x\right)+\left(10x-5\right)$

Factor out 2x from 4x² -2x : 2x(2x-1)

Factor out 5 from 10x - 5 : 5(2x - 1)

Put together: $=2x\left(2x-1\right)+5\left(2x-1\right)$

Factor out 2x - 1: $=\left(2x-1\right)\left(2x+5\right)$

xcookiex12

8/19/2022

4 0

2 years ago

Determine whether the ratios are equivalent. 3 : 10 and 9 : 25 Please Help!!

Ilia_Sergeevich [38]

Answer:

They aren't

Step-by-step explanation:

9/25 / 3= 3/8.3

3/10 x 3 = 9/30

none of those equal to each other

7 0

3 years ago

What is the least common multiple of 14 21 and 28

Maru [420]

Answer:

it's 84

Step-by-step explanation:

I (did) the math for you

(look it up)

8 0

3 years ago

Read 2 more answers

BEST ANSWER GETS BRAINLIEST!!

777dan777 [17]

2 over 3 plus 5 equals 5 and 2 over 3

3 0

3 years ago

Read 2 more answers

The heights of 40 randomly chosen men are measured and found to follow a normal distribution. An average height of 175 cm is obt

AVprozaik [17]

Answer:

95% two-sided confidence interval for the true mean heights of men is [168.8 cm , 181.2 cm].

Step-by-step explanation:

We are given that the heights of 40 randomly chosen men are measured and found to follow a normal distribution.

An average height of 175 cm is obtained. The standard deviation of men's heights is 20 cm.

Firstly, the pivotal quantity for 95% confidence interval for the true mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average height = 175 cm

$\sigma$ = population standard deviation = 20 cm

n = sample of men = 40

Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.

So, 95% confidence interval for the true mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

level of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ ]

= [ $175-1.96 \times }{\frac{20}{\sqrt{40} } }$ , $175+1.96 \times }{\frac{20}{\sqrt{40} } }$ ]

= [168.8 cm , 181.2 cm]

Therefore, 95% confidence interval for the true mean height of men is [168.8 cm , 181.2 cm].

The interpretation of the above interval is that we are 95% confident that the true mean height of men will be between 168.8 cm and 181.2 cm.

3 0

3 years ago