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nadezda [96]
3 years ago
12

According to Arrhenius, NH4+ an acid or a base? Write an equation to support

Chemistry
1 answer:
sergejj [24]3 years ago
8 0

According to Arrhenius definition of acids, NH4^+ is an acid.

According  to Arrhenius  definition of acids and bases, acid is any substance that produces hydrogen ion in solution as its only positive ion.

Following this definition, let us now consider what happens when NH4^+ is introduced into a water;

NH4^+(aq)-------> NH3(aq) + H^+(aq)

Hence, according to Arrhenius definition of acids, NH4^+ is an acid.

For another example of Arrhenius acids, see

brainly.com/question/516295

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An ion of iron has an 26 protons, 30 neutrons, and 23 electrons. What are its atomic number, atomic mass, and net charge?
kirill [66]
The answer to ur question corresponds to the information u provided in option A.
please mark  me brainiest on this and thank me 
6 0
4 years ago
Read 2 more answers
How many moles of oxygen (O2) are present in 33. 6 L of the gas at 1 atm and 0°C? 1. 5 2 22. 4 32.
oee [108]

The number of moles of oxygen in the gas is 1.5 L.

The correct option is (A).

<h3>What are moles? </h3>

The mole is the International System of Units' foundation unit of material quantity.

Given,

The volume of gas is 33.6 L

Pressure is 1 atm.

Temperature is 0°C

Molar gas volume is 22.4 L

There is no temperature and pressure is 1 atm.

By formula of moles, volume is divided by molar mass

\bold{\dfrac{33.6}{22.4 } =1.5\; mole}

Thus, option A is correct. 1.5 L.

Learn more about gas, here:

brainly.com/question/13123721

3 0
2 years ago
Calculate the amount of heat released in the combustion of 10.5 grams of Al with 3 grams of O2 to form Al2O3(s) at 25°C and 1 at
ElenaW [278]

Answer : The amount of heat released in the combustion is, 209.5 kJ

Explanation :

First we have to calculate the moles of Al and O_2.

\text{ Moles of }Al=\frac{\text{ Mass of }Al}{\text{ Molar mass of }Al}=\frac{10.5g}{27g/mole}=0.389moles

\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{3g}{32g/mole}=0.188moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction will be:

4Al+3O_2\rightarrow 2Al_2O_3

From the balanced reaction we conclude that

As, 3 mole of O_2 react with 4 mole of Al

So, 0.188 moles of O_2 react with \frac{4}{3}\times 0.188=0.251 moles of Al

From this we conclude that, Al is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of Al_2O_3

From the reaction, we conclude that

As, 3 mole of O_2 react to give 2 mole of Al_2O_3

So, 0.188 moles of O_2 react to give \frac{2}{3}\times 0.188=0.125 moles of Al_2O_3

Now we have to calculate the amount of heat released in the combustion.

As, 1 mole of Al_2O_3 releases amount of heat = 1676 kJ

So, 0.125 mole of Al_2O_3 releases amount of heat = 0.125\times 1676kJ=209.5kJ

Thus, the amount of heat released in the combustion is, 209.5 kJ

4 0
3 years ago
**98 POINTS**
Andrei [34K]

OP already did it - CONGRATS!!

here are the steps 2 get the same ans:

(NH4)2 CO3 has 2x N, 8x H, 1x C and 3x O per molecule

so its molecular mass = 2x14 + 8x1 + 1x12 + 3x16

=28+8+12+48

=96g

of that 96g, 8x1=8g is due to Hydrogen

so by ratio n proportion, 1.00g will have 1x8/96 = 1/12g = 0.083g of H

3 0
3 years ago
Pleasee help me with this :)
Marysya12 [62]

1) Water And Wind

2) Wind Breaks

3 0
4 years ago
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