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Rufina [12.5K]
3 years ago
15

What are adipoyl chloride used for or uses?

Chemistry
1 answer:
Alexxandr [17]3 years ago
3 0

Answer:

Explanation:

It is a colorless liquid. It reacts with water to give adipic acid. It is prepared by treatment of adipic acid with thionyl chloride.

Adipoyl Chloride can be used in the synthesis of nylon. Also it is used in the synthesis of chiral polymer for membrane application.

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PLEASE HELPPPP
Y_Kistochka [10]

physical, mathematical, and conceptual are the 3 types of models an example of a conceptual model is a model of our solar system or even a rocket a limitation of them is they are not realistic in scale but allow us see arrangements of things. mathematical models could be something like a formula graph charts ect we benefit from the visual steps however the downfall is there's lots of user error and a physical model is something like an atom model it allows to see the thing but it's physical states limits us

7 0
3 years ago
The pOH of a solution is 9.70. what is the H+ concentration in the solution ?
Scrat [10]

Answer:

The H+ concentration is 10^{-4.3} M

Explanation:

We know that for any solution,

pOH + pH = 14

Given,

pOH = 9.70,

Therefore using formula,we get,

pH = 14 - pOH,

pH = 14 - 9.70;

pH = 4.30

We also know,

If Concentration of H+ in a solution in C,

Then,

pH = -log(C) ------(Formula 1) and  C = 10^{-pH}  ----(Formula 2)

Therefore,

using formula 2, we get,

C = 10^{-pH}  

C = 10^{-4.30}M.

Therefore concentration of H+ in the given solution is 10^{-4.3} M

6 0
3 years ago
How many moles of Kr are contained in 398 mg of Kr?
bagirrra123 [75]
The mass of 1 mole of an element is its atomic weight on the Periodic Table in grams.

1g = 1000mg

The mass of 1 mole of Kr = 83.80g Kr

Convert mg Kr to g Kr.

398mg Kr x (1g/1000mg) = 0.398g Kr

Convert g Kr to mol Kr.

0.398g Kr x (1mol Kr/83.80g Kr) = 4.75x10-3mol Kr
8 0
3 years ago
Which two substances are among the four major types of organic
Sedbober [7]

Answer:

B.Carbohydrates and D. water

5 0
3 years ago
Read 2 more answers
What is the concentration of the hydroxide ion? Given that the concentration of the hydronium ion is 2.3 X 10^-7 M
professor190 [17]

Answer:

4.35 * 10^-8 M

Explanation:

Since the concentration of the hydronium ion= 2.3 X 10^-7 M

And we know that;

[H3O^+] [OH^-] = 1 * 10^-14

[H3O^+]  = concentration of the hydronium ion

[OH^-] = concentration of the hydroxide ion

So;

[OH^-] =1 * 10^-14/[ H3O^+]

But [H3O^+] = 2.3 X 10^-7 M

[OH^-] = 1 * 10^-14/2.3 X 10^-7

[OH^-] = 4.35 * 10^-8 M

8 0
3 years ago
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