Answer : The concentration of the NaOH solution is, 0.738 M
Explanation :
To calculate the concentration of base, we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is NaOH.
We are given:

Putting values in above equation, we get:


Thus, the concentration of the NaOH solution is, 0.738 M
What are biotic and abiotic factors?
Biotic and abiotic are the two essential factors responsible for shaping the ecosystem. The biotic factors refer to all the living beings present in an ecosystem, and the abiotic factors refer to all the non-living components like physical conditions (temperature, pH, humidity, salinity, sunlight, etc.) and chemical agents (different gases and mineral nutrients present in the air, water, soil, etc.) in an ecosystem. Therefore, both the abiotic and biotic resources affect the survival and reproduction process.
Answer:
Abiotic factors in the tropical rainforest include humidity, soil composition, temperature, and sunlight. A limiting factor in the ecosystem is that canopy layers block sunlight from reaching the forest floor, causing shorter plants to not be able to grow. Biotic factors in the tropical rainforest include orchids, lilies, heliconia, and bromeliads. Tropical rainforests can have various fungi, shrubs, herbs, woody vines, lichens, and mosses. The trees making up the rainforest canopy include the tonka bean wood, teak, rubber, and several species of evergreens and palm trees. This way the organisms in the tropical rainforest both depend on biotic and abiotic factors.
Answer:
The answer is pyruvate → lactate
Explanation:
In the reaction of glycolysis, glucose breaks down to form pyruvate yielding ATP and NADH.
Under or during strenuous exercise, which is an anaerobic condition, lactate is formed by the reoxidization of NADH and the conversion of pyruvate to lactate.
Answer:
(1) Bromination, (2) E2 elimination and (3) epoxidation
Explanation:
- In the first step, -OH group in cyclopentanol is replaced by more facile leaving group Br by treating cyclopentanol with

- In the second step, E2 elimination in presence of strong base e.g. NaOEt/EtOH produce cyclopentene
- In the third step, treatment of cyclopentene with mCPBA produces 1,2-epoxycyclopentane
- Full reaction scheme has been shown below
Air moves when the molecules are free meaning they aren't close up to each other or trying to fill up space, they are moving freely.