Answer:
x = -4, x = 1
Step-by-step explanation:
Now I do not know why you said done, but just saying, if you are done with a question, you should delete it. Now I am just going to assume you knew this and move on with the solution of the problem.
When you factor this equation, you will get (x+4)(x-1).
 
You can then solve for x using zero product property. The first root is -4 and the second root is 1.
 
        
             
        
        
        
Answer:

Step-by-step explanation:

 
        
             
        
        
        
Answer:
Step-by-step explanation:
Here's how you convert:
  The little number outside the radical, called the index, serves as the denominator in the rational power, and the power on the x inside the radical serves as the numerator in the rational power on the x.
A couple of examples:
![\sqrt[3]{x^4}=x^{\frac{4}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E4%7D%3Dx%5E%7B%5Cfrac%7B4%7D%7B3%7D)
![\sqrt[5]{x^7}=x^{\frac{7}{5}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E7%7D%3Dx%5E%7B%5Cfrac%7B7%7D%7B5%7D)
It's that simple. For your problem in particular:
 is the exact same thing as ![\sqrt[3]{7^1}=7^{\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B7%5E1%7D%3D7%5E%7B%5Cfrac%7B1%7D%7B3%7D)
 
        
             
        
        
        
Y=(3x+4)(-2x-3)=-6x^2-4x-9x-12=-6x^2-13x-12.
It is a quadratic function because it has x in power 2 (x^2)
        
                    
             
        
        
        
The decimal multiplier to decrease by 30 is .7