If the length of a string increases 2 times but the mass of the string remains constant, the original density will be multiplied by a factor mathematically given as
v=1.414 times
<h3>Will the new density of the string equal the original density multiplied by what factor?</h3>
Generally, the equation for the volume is mathematically given as
v = sqt(TL/m)
Where
density = mass/length
Therefore
![v2/v1 = \sqrt{L2/L1}](https://tex.z-dn.net/?f=v2%2Fv1%20%3D%20%5Csqrt%7BL2%2FL1%7D)
![v2/v1 = \sqrt{2}](https://tex.z-dn.net/?f=v2%2Fv1%20%3D%20%5Csqrt%7B2%7D)
In conclusion,v ratio will give us
v=1.414 times
Read more about volume
brainly.com/question/1578538
It’s written by some one that was there as show on google your welcome
Answer:
True
Explanation:
Dispensing chemical from large stock bottles into smaller container makes sure that students only takes the quantity they need which reduces wastage. Also in situation where the students did not finish the reagent or chemical it is easier for student to pour back into smaller bottle than the entire reagent bottle which can contaminate the whole solution. Small bottles prevent or reduces the risk of spillage because it is easier to handle and pour.